[英]R extract substring from end of pattern until first occurance of character
努力争取这场比赛并在R gsub
取代工作仍然没有成功。 我试图在一个字符串中匹配模式"Reason:"
,并在此模式之后接触所有内容,直到第一次出现一个点( .
)例如:
Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE.
会回来"Not interested"
这是一个解决方案:
s <- "Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE."
sub(".*Reason: (.*?)\\..*", "\\1", s)
# [1] "Not interested"
更新 (发表评论):
如果你还有与模式不匹配的字符串,我建议使用regexpr
而不是sub
:
s2 <- c("no match example",
"Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE.")
match <- regexpr("(?<=Reason: ).*?(?=\\.)", s2, perl = TRUE)
ifelse(match == -1, NA, regmatches(s2, match))
# [1] NA "Not interested. ChannelID: CARE"
对于第二个示例,您可以使用以下正则表达式:
s3 <- "Delete Payment Arrangement of type Proof of Payment for BAN : 907295267 on date 02/01/2014, from reason PAERR."
# a)
sub(".*type (.*?) for.*", "\\1", s3)
# [1] "Proof of Payment"
# b)
match <- regexpr("(?<=type ).*?(?= for)", s3, perl = TRUE)
ifelse(match == -1, NA, regmatches(s3, match))
# [1] "Proof of Payment"
许多不同的方式(从提交中可以看出)。 我个人喜欢使用stringr
函数。
library(stringr)
rec <- "Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE."
str_match(rec, "Reason: ([a-zA-Z0-9\ ]+)\\.")[2]
## [1] "Not interested"
这将有效:
x <- "Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE."
library(qdap)
genXtract(x, "Reason:", ".")
## Reason: : .
## " Not interested"
使用regexepr和regmatches:
str <- "Offer Disposition. MSISDN: 7183067962. Offer: . Disposition: DECLINED. Reason: Not interested. ChannelID: CARE."
m<-regexpr("(?<=Reason: )[^.]+", str, perl=TRUE)
regmatches(str, m)
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