Python正则表达式搜索和分组

Question

04:38:06.151 [http-bio-5443-exec-8] INFO  A.g.r.q.r.flex.RubixService   - [NO-ID] [Mar 26, 2014 04:38:06 UTC] -     [5a-y2-24C363B223F1CB534B8DCA5693ADF2E9] --0->servAggregateMultiple:61224380032:[[{"responseMeasures":    ["SubscriberCnt","UpBytes","DownBytes","SessionCount","SubscriberPercentage","UpBytesPercentage","DownBytesPercentage","SessionCountPercentage"]
"sortProperty":"SubscriberCnt"

我在一个文本文件中有此数据。 我想执行搜索并找到responseMeasures，其中有此数据块。 如果找到它，我想在此之后存储所有内容：

["SubscriberCnt","UpBytes","DownBytes","SessionCount","SubscriberPercentage","UpBytesPercentage","DownBytesPercentage","SessionCountPercentage"]

我想将其作为组存储在变量中。 类似地，我希望找到findProperty并将“ SubscriberCnt”作为一个组存储在变量中。

这是我的代码段：

import re
fo = open("data.txt", "r")
data = fo.readlines()
for n in data:
        matchMeasure = re.search("responseMeasures:", n)
        if matchMeasure:
                measureData =  matchMeasure.groups()
                print "Measures are" +  str(measureData)
        matchDimension = re.search("sortProperty", n)
        if matchSort:
                sortData = matchSort.groups()
                print "Group by" + str(sortData)

这段代码可能不是最好的方法，而只是显示我在寻找什么。

我想要的预期输出：-

Meausres are:-
SubscriberCnt
UpBytes
DownBytes
SessionCount
SubscriberPercentage
UpBytesPercentage
DownBytesPercentage
SessionCountPercentage"
Group by SubscriberCnt

Answer 1

您可以使用re.findall来实现

with open('data.txt','r') as f:

    first_filter = re.findall(r"[\w']+", f.read())
    measures = first_filter[first_filter.index('responseMeasures')+1:first_filter.index('sortProperty')]
    sortby = first_filter[first_filter.index('sortProperty')+1::]

    for measure in measures:
        print measure

    print "Group by:"

    for sort_type in sortby:
        print sort_type