python正则表达式分组

Question

给定字符串s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'

我想得到以下输出： (C /something_3),/,(D /something_4)(D /something_5)

我一直在匹配整个字符串s，而不是在子字符串之上。

我正在使用re.search(r'(\\(C.*\\)),/,(\\(D.*\\))+')

任何帮助表示赞赏...

Answer 1

您就在那里re.search(r'(\\(C.*\\)),/,(\\(D.*\\))+', s).group()将为您提供所需的东西。

>>> import re
>>> s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'
>>> re.search(r'(\(C.*\)),/,(\(D.*\))+', s).group()
'(C /something_3),/,(D /something_4)(D /something_5)'

您是否希望将其进一步分组？

Answer 2

使用Python 2.7，我得到的确切结果是：

import re
s = '(A /something_1)(B /something_2)(C /something_3),/,(D /something_4)(D /something_5)'
m = re.search(r'(\(C.*\)),/,(\(D.*\))+', s)

s[m.start():m.end()] == '(C /something_3),/,(D /something_4)(D /something_5)'