如何获取已注册电子邮件的主键ID

Question

我的项目目前正在进行中有问题，这是我的电子邮件控制器，我想获取在我的数据库中注册的电子邮件的ID

      if ($this->getRequest()->isPost()) {

        $formData = $this->getRequest()->getPost();

        if ($form->isValid($formData)) {
        $imail = $form->getValue('email');
            $users = new Application_Model_DbTable_Users();
            $row = $users->fetchRow($users->select('uid')->where('email = ".$imail."'));

        /*  if ($row == 1) {
                    $token = uniqid(mt_rand(), true);
                    $userpass = new Application_Model_DbTable_Password();
                    $userpass->addToken($uid , $token);
                } else { $this->view->errorMessage = "Email not registered"; }
            */
        //$this->emailAction();
        }

我只需要让id能够转移到我的下一个功能，但我也不能这样做我认为这可能是无关的但我在纯PHP上做了这个并且工作正常

       if (isset($_POST['submit'])) {

    $email = $_POST['email'];

    $getemail = mysql_query("SELECT `uid` FROM `users` WHERE `email` ='$email'");

    $resemail = mysql_num_rows($getemail);


        if ($resemail == 0) {

            echo "Email id is not registered";

        }

            $token = uniqid(mt_rand(), true);

            $getoken = mysql_query("INSERT INTO `password_recovery` (`uid`,`token`) VALUES ((SELECT `uid` FROM `users` WHERE `email` = '$email'),'$token') ");

我怎么能在zendframework中做这个逻辑1谢谢

Answer 1

Jehad Keriaki的解决方案是正确的，但不安全。 使用预准备语句语法，例如：

$row = $users->fetchRow($users->select('uid')->where('email = ?', $imail));

它将保护您免受SQL注入攻击。

Answer 2

尝试改变

$row = $users->fetchRow($users->select('uid')->where('email = ".$imail."'));

至

$row = $users->fetchRow($users->select('uid')->where('email = "$imail"'));

我认为问题在于点，你仍然可以用作：

$row = $users->fetchRow($users->select('uid')->where('email = "'.$imail.'"'));