[英]how to get primary key id of a registered email
我的項目目前正在進行中有問題,這是我的電子郵件控制器,我想獲取在我的數據庫中注冊的電子郵件的ID
if ($this->getRequest()->isPost()) {
$formData = $this->getRequest()->getPost();
if ($form->isValid($formData)) {
$imail = $form->getValue('email');
$users = new Application_Model_DbTable_Users();
$row = $users->fetchRow($users->select('uid')->where('email = ".$imail."'));
/* if ($row == 1) {
$token = uniqid(mt_rand(), true);
$userpass = new Application_Model_DbTable_Password();
$userpass->addToken($uid , $token);
} else { $this->view->errorMessage = "Email not registered"; }
*/
//$this->emailAction();
}
我只需要讓id能夠轉移到我的下一個功能,但我也不能這樣做我認為這可能是無關的但我在純PHP上做了這個並且工作正常
if (isset($_POST['submit'])) {
$email = $_POST['email'];
$getemail = mysql_query("SELECT `uid` FROM `users` WHERE `email` ='$email'");
$resemail = mysql_num_rows($getemail);
if ($resemail == 0) {
echo "Email id is not registered";
}
$token = uniqid(mt_rand(), true);
$getoken = mysql_query("INSERT INTO `password_recovery` (`uid`,`token`) VALUES ((SELECT `uid` FROM `users` WHERE `email` = '$email'),'$token') ");
我怎么能在zendframework中做這個邏輯1謝謝
Jehad Keriaki的解決方案是正確的,但不安全。 使用預准備語句語法,例如:
$row = $users->fetchRow($users->select('uid')->where('email = ?', $imail));
它將保護您免受SQL注入攻擊。
嘗試改變
$row = $users->fetchRow($users->select('uid')->where('email = ".$imail."'));
至
$row = $users->fetchRow($users->select('uid')->where('email = "$imail"'));
我認為問題在於點,你仍然可以用作:
$row = $users->fetchRow($users->select('uid')->where('email = "'.$imail.'"'));
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