通过subprocess.check_output运行Git脚本时，其运行方式有所不同吗？

Question

当我运行此Bash脚本时

#!/bin/bash

cd /srv/http
unset GIT_DIR

git commit -am "design changes"
git push -u origin master
git checkout dev
git merge master
git commit -am "design changes"
git checkout master

通过命令行，我得到这个输出

[master 914422f] design changes
 1 file changed, 17 deletions(-)
Counting objects: 3, done.
Delta compression using up to 2 threads.
Compressing objects: 100% (3/3), done.
Writing objects: 100% (3/3), 334 bytes | 0 bytes/s, done.
Total 3 (delta 2), reused 0 (delta 0)
To https://blah@bitbucket.org/blah/blah.git
   562207f..914422f  master -> master
Branch master set up to track remote branch master from origin.
Switched to branch 'dev'
Updating 562207f..914422f
Fast-forward
 save-design | 17 -----------------
 1 file changed, 17 deletions(-)
On branch dev
nothing to commit, working directory clean
Switched to branch 'master'
Your branch is up-to-date with 'origin/master'.

但是当我使用Python通过Python运行它时

subprocess.check_output('./save-design', shell=True)

我得到这个输出

M   save-design
Already up-to-date.
M   save-design
Your branch is up-to-date with 'origin/master'.

为什么会这样？

Answer 1

我仍然不知道为什么会这样，但是我通过将其切换到本地主机来运行它来修复它：

subprocess.check_output('ssh localhost "/srv/http/save-design"', shell=True)