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使用PHP mcrypt的AES128加密输出与ASP.net相同

[英]AES128 Encryption using PHP mcrypt is not outputting same as ASP.net

我有一个PHP应用程序,需要对ASP.net Web服务使用的质询字符串进行加密,但是.net无法正确解密我的PHP实现的输出。 正是在这个与iOS和.net有关的问题中: AES128位加密字符串与.net上的相似

为什么输出不同?我如何对PHP进行输出以使其与.net相同?

我的PHP代码如下所示:

$key = '128bit-16bytekey';
$value = '128bit-16byteval';
function fnEncrypt($value, $key)
{
    $ivsize = mcrypt_get_iv_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_ECB);
    $iv     = mcrypt_create_iv($ivsize);
    return base64_encode(
            mcrypt_encrypt(
                MCRYPT_RIJNDAEL_128,
                $key, $value, 
                MCRYPT_MODE_ECB,$iv
            ));
}

像这样的.net

public static string EncryptData(string plainText)
    {
        string encryptionKey = AppConstants.AES_ENCRYPTDECRYPT_KEY;
        // Convert our plaintext into a byte array.
        // Let us assume that plaintext contains UTF8-encoded characters.
        byte[] plainTextBytes = Encoding.UTF8.GetBytes(plainText);

        // Use the password to generate pseudo-random bytes for the encryption
        // key. Specify the size of the key in bytes (instead of bits).
        ASCIIEncoding encoding = new ASCIIEncoding();
        byte[] keyBytes = new byte[16];

        byte[] tempKey = encoding.GetBytes(encryptionKey);

        for (int i = 0; i < keyBytes.Length; i++)
        {
            if (i < tempKey.Length)
            {
                keyBytes[i] = tempKey[i];
            }
            else
            {
                keyBytes[i] = 0;
            }
        }

        // Create uninitialized Rijndael encryption object.
        RijndaelManaged symmetricKey = new RijndaelManaged();

        //AesManaged symmetricKey = new AesManaged();


        //symmetricKey.Padding = PaddingMode.PKCS7;
        // It is reasonable to set encryption mode to Cipher Block Chaining
        // (CBC). Use default options for other symmetric key parameters.
        symmetricKey.Mode = CipherMode.ECB;

        // Generate encryptor from the existing key bytes and initialization 
        // vector. Key size will be defined based on the number of the key 
        // bytes.

        //ICryptoTransform encryptor = symmetricKey.CreateEncryptor(keyBytes,initVectorBytes);
        ICryptoTransform encryptor = symmetricKey.CreateEncryptor(keyBytes, null);

        // Define memory stream which will be used to hold encrypted data.
        MemoryStream memoryStream = new MemoryStream();

        // Define cryptographic stream (always use Write mode for encryption).
        CryptoStream cryptoStream = new CryptoStream(memoryStream,
                                                     encryptor,
                                                     CryptoStreamMode.Write);
        // Start encrypting.
        cryptoStream.Write(plainTextBytes, 0, plainTextBytes.Length);

        // Finish encrypting.
        cryptoStream.FlushFinalBlock();

        // Convert our encrypted data from a memory stream into a byte array.
        byte[] cipherTextBytes = memoryStream.ToArray();

        // Close both streams.
        memoryStream.Close();
        cryptoStream.Close();

        // Convert encrypted data into a base64-encoded string.
        string cipherText = Convert.ToBase64String(cipherTextBytes);

        // Return encrypted string.
        return cipherText;
    }

样本输出

PHP的:Q54nP / tXq2rDTUwWw4ckkg ==

.net:Q54nP / tXq2rDTUwWw4ckkpSt9CQiIzsg2xsQEndcqc8 =

PHP的:DQZdAB / lABXVOOoCdNM6HQ = =

.net:DQZdAB / lABXVOOoCdNM6HZSt9CQiIzsg2xsQEndcqc8 =

就像上面提到的问题一样,.net输出的右侧始终是相同的,而这两个实现之间的左侧是一致的。 我很确定IV是无关紧要的,这与mcrypt中填充的处理方式有关。

如果我解密PHP中的任何输出,它将返回相同的正确结果。

谁能阐明任何想法? 我无法更改.net应用。 谢谢!

发生这种情况是由于.net中应用了填充。 您可以通过在.net代码中添加以下行来克服这一问题:

symmetricKey.Padding = PaddingMode.None;

或者,您可以更改PHP代码以获取相同的加密字符串:

// Add the lines below to your fnEncrypt function
$block = mcrypt_get_block_size(MCRYPT_RIJNDAEL_128, MCRYPT_MODE_ECB);
$len = strlen($value);
$padding = $block - ($len % $block);
$value .= str_repeat(chr($padding),$padding);

PHP手册页中的注释之一描述了类似的问题: http : //www.php.net//manual/en/function.mcrypt-encrypt.php#47973

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