matplotlib错误栏图-使用自定义颜色图

Question

我正在尝试为x轴上的每个点制作一个具有不同颜色的误差线图。 错误条形图本身可以很好地显示，但是当我尝试使用颜色图时它会炸弹，因此我必须做错了。 这是我想要做的一个人为的示例：

import matplotlib.pyplot as plt

colors = ["b","g","c","m","y","k","r","g","c","m","y","k",
          "b","g","c","m","y","k","r","g","c","m","y","k"]

xlabels = ['A','B','8','14']

xval = [0, 1, 2, 3]
yval = [0, 1, 4, 9]
yerr = [0.5, 0.4, 0.6, 0.9]


cmap = dict(zip( xval,colors))

现在，运行此命令后，我可以去：

plt.errorbar(xval, yval, yerr=yerr, color='b')

这给了我下面的图表（即，它可以工作。但是当我尝试这样做时：

plt.errorbar(xval, yval, yerr=yerr, color=cmap)

它给了我一个错误，例如“ ValueError：to_rgba：Invalid rgba arg“ {0：'b'，1：'g'，2：'c'，3：'m'}”

可以做我想做的事吗？ 我试图做的是让误差条形图中的4个点中的每个点都有不同的颜色。 我真的不需要连接这些点的线。 感谢任何帮助/建议。

Answer 1

我已经提到过，您可以遍历每个特定的点/颜色。

另一个解决方案是在您的errorbar图中使用scatter ，就像这个问题一样 。 代码如下

import matplotlib.pyplot as plt

colors = ["b","g","c","m","y","k","r","g","c","m","y","k",
          "b","g","c","m","y","k","r","g","c","m","y","k"]

xlabels = ['A','B','8','14']

xval = [0, 1, 2, 3]
yval = [0, 1, 4, 9]
yerr = [0.5, 0.4, 0.6, 0.9]

plt.scatter(xval, yval, c=colors, s=50, zorder=3)
plt.errorbar(xval, yval, yerr=yerr, zorder=0, fmt="none",
             marker="none")

plt.savefig("scatter_error.png", dpi=300)
plt.show()

结果如下