从R中的文本中提取模式

Question

我的数据如下：

t <- "The data is like hi hi hi hi  and hi hi end"

我的正则表达式是：

grammer <- "[[:space:]]*(hi)+[[:space:]]"

执行以下两行后：

res <- gregexpr(grammer, t)
regmatches(t, res)

我有输出：

 [[1]]
 [1] " hi " "hi "  "hi "  "hi "  " hi " "hi " 

但是，我想要的东西是： " hi hi hi hi "和" hi hi "

Answer 1

你可以这样做，

> t<-"The data is like hi hi hi hi  and hi hi end"
> grammer<-"[[:space:]]*(hi[[:space:]])+[[:space:]]*"
> res<-gregexpr(grammer, t)
> regmatches(t, res)
[[1]]
[1] " hi hi hi hi  " " hi hi "  

要么

> grammer<-"[[:space:]]*(hi[[:space:]])+"
> res<-gregexpr(grammer, t)
> regmatches(t, res)
[[1]]
[1] " hi hi hi hi " " hi hi " 

要么

> t <- "The data is like hi hi hi hi and hi hi end hi"
> grammer<-"[[:space:]]*(hi\\>[[:space:]]?)+"
> res<-gregexpr(grammer, t)
> regmatches(t, res)
[[1]]
[1] " hi hi hi hi " " hi hi "       " hi"

没有领先或跟随空格。

> t <- "The data is like hi hi hi hi and hi hi end hi"
> grammer<-"hi\\>([[:space:]]hi)*"
> res<-gregexpr(grammer, t)
> regmatches(t, res)
[[1]]
[1] "hi hi hi hi" "hi hi"       "hi"

说明：

• [[:space:]]*匹配空格字符零次或多次。
• (hi[[:space:]])+匹配字符串hi和后续空格一次或多次。