[英]Returning contents of a text file and printing different value
我正在制作一本食谱书,目前可以创建食谱,但是现在我开始构建搜索和显示已存储食谱的模块。
目前,我有一个.txt文档,其内容大致如下:
威廉姆斯特别食谱
配料:
面包:120克黄油:1234克
食谱服务:12
然后,我问用户要提供多少食物,并根据多少种食谱,我需要将所有配料数量乘以该数量。 然后,我需要重新打印完整的配方。
我想知道我将如何实现这一结果,而不是专门要求编码响应作为答案,但是我将非常感谢我将如何完成这项任务以及所需的任何特定功能。
到目前为止,我还包含了我的代码,我欣赏它目前还非常杂乱无章,并且可能很难理解,但我将其包括在内以供参考。
(我还创建了所有已创建食谱的.txt文件,稍后将以向用户显示所有食谱的方式来实现该文件,但此刻它仅是为搜索而设置的。)
#Recipe Task
import os.path
def file_(n):
if n == "listR" :
list_f = open("list_recipes.txt", "a+")
list_f.write(new_name + "\n")
if n == "oar": #open append read
f=open(new_name + ".txt","a+")
elif n == "c": #closes file
f.close()
def print_line(x): #ease of printing multiple lines to break up text
for c in range(x):
print ""
def new_ingredients(): #adding new ingredients
f.write("Ingredients:" + "\n" + "\n")
fin_ingredient = False
while fin_ingredient != True :
input_ingredient = raw_input("New ingredient:" + "\n").lower()
split_ingred = input_ingredient.split()
if input_ingredient == "stop": #stops asking questions when user types 'stop'
fin_ingredient = True
else :
f.write(split_ingred[0] + ":" + " " + split_ingred[1] + " " + split_ingred[2] + "\n")
def search_recipe(n): #searching for recipes
n = n + ".txt"
if os.path.isfile('/Users/wjpreston/Desktop/' + n) == True :
print "Recipe Found..."
found_recipe = open(n)
print found_recipe.read()
append_serving = raw_input("Would you like to change the number of people you are serving?" + "\n").lower()
if append_serving == "yes" :
appended_serving = input("How many would you like to serve?" + "\n")
with open(n) as f: #here is my issue - not sure where to go with this!!
list_recipe = f.readlines()
found_recipe.close()
else :
print "fail"
else:
print "No existing recipes under that name have been found."
print "Welcome to your Recipe Book"
print_line(3)
recipe_phase = raw_input("Are you 'creating' a recipe or 'viewing' an existing one?" + "\n").lower()
if recipe_phase == "creating":
new_name = raw_input("Name of Recipe: " + "\n")
file_("listR")
file_("oar")
f.write("------------" + "\n" + new_name + "\n" + "\n")
print "Ingrediants required in the format 'ingredient quantity unit' - type 'stop' to end process"
new_ingredients()
new_num = input("Number serving: ")
f.write("\n" + "Recipe Serves: " + str(new_num) + "\n" "\n" + "\n")
file_("c")
elif recipe_phase == "viewing":
search = raw_input("Search for recipe: ")
search_recipe(search)
我不是处理字符串的专家,但是我会通过以下方式解决您的问题:
将每种成分保存在新行中。
用“ \\ n”分隔加载的字符串。
然后使用一些for循环处理列表,同时创建两个字典,一个用于实际数据
e.g. {"bread": 4, "butter": 7}
一种用于每种成分的类型:
e.g. {"bread": grams, "butter": grams}
您还应该保存为配方写的份量,以及配料的顺序(字典以随机顺序存储):
e.g. ["bread", "butter"]
之后,您可以询问您的客户他有多少份服务,然后最终计算并打印最终结果。
for ing in ing_order:
print ing+":", ing_amount[ing]*requested_serves/default_seves, ing_types[ing]
...希望您仍然有足够的挑战,希望我能正确理解您的问题。
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