将CSV文件的内容转换为字典

Question

到目前为止我的代码是一个基本上读取csv文件并打印其内容的函数：

def read(filename):
    with open(filename, 'r') as csvfile:
        reader = csv.reader(csvfile, delimiter=',')
        for row in reader:
            print(row)

sailor.csv内容：

name, mean performance , std dev
Alice, 100, 0,
Bob, 100, 5,
Clare, 100, 10,
Dennis, 90, 0,
Eva, 90, 5,

read('sailor.csv')并运行该函数

电流输出：

['name', ' mean performance ', ' std dev']
['Alice', ' 100', ' 0', '']
['Bob', ' 100', ' 5', '']
['Clare', ' 100', ' 10', '']
['Dennis', ' 90', ' 0', '']
['Eva', ' 90', ' 5', '']

所需产量：

{'Dennis': (90.0, 0.0), 'Clare':(100.0, 10.0), 
'Eva': (90.0, 5.0), 'Bob': (100.0, 5.0), 'Alice': (100.0, 0.0)}

任何想法如何实现这一输出？ 如果有帮助，请使用Python 3.4.2，我们将非常感谢您对答案的解释！

Answer 1

使用csv标准库和字典理解...

import csv
with open('sailor.csv') as csvfile:
   reader = csv.reader(csvfile)
   next(reader)
   d = {r[0] : tuple(r[1:-1]) for r in reader}

其中d将是你想要的字典。 d[1:-1]将数组从第二个切换到第二个到最后一个元素。

编辑：跳过标题，转换为元组

Answer 2

我想这就是你想要的：

import csv

def read(filename):
    out_dict = {}
    with open(filename, 'r') as csvfile:
        reader = csv.reader(csvfile, delimiter=',')
        next(csvfile) # skip the first row
        for row in reader:
            out_dict[row[0]] = float(row[1]), float(row[2])
            print(row)

    return out_dict

print(read('data.csv'))   

打印：

{'Bob': (' 100', ' 5'), 'Clare': (' 100', ' 10'), 'Alice': (' 100', ' 0'), 'Dennis': (' 90', ' 0'), 'Eva': (' 90', ' 5')}

这里解释不多。 只需将值放入字典中，并跳过添加的第一行。 我认为人名是独一无二的。

Answer 3

所以...我知道这个问题已经得到了回答，但我认为我只是在混合中添加一个单行来增加缩短答案：

from csv import reader
from itertools import islice

{r[0] : tuple(r[1:-1]) for r in islice(reader(open('sailor.csv')), 1, None)}

唯一真正新颖的事情是添加islice以干净地跳过标题行。

Answer 4

使用DictReader：

def read(filename):
    with open(filename, 'r') as csvfile:
        reader = csv.DictReader(csvfile, delimiter=',')
        for row in reader:
            print(row)

Answer 5

如果我可以，这是我的解决方案：

>>> import pyexcel as pe
>>> s = pe.load("sailor.csv", name_rows_by_column=0, name_columns_by_row=0)
>>> s.format(float)
>>> s
Sheet Name: csv
+--------+------------------+---------+---+
|        | mean performance | std dev |   |
+========+==================+=========+===+
| Alice  | 100              | 0       | 0 |
+--------+------------------+---------+---+
| Bob    | 100              | 5       | 0 |
+--------+------------------+---------+---+
| Clare  | 100              | 10      | 0 |
+--------+------------------+---------+---+
| Dennis | 90               | 0       | 0 |
+--------+------------------+---------+---+
| Eva    | 90               | 5       | 0 |
+--------+------------------+---------+---+
>>> del s.column[''] # delete the column which has '' as its name
>>> s.to_dict(True) # make a dictionary using row names as key
OrderedDict([('Alice', [100.0, 0.0]), ('Bob', [100.0, 5.0]), 
('Clare', [100.0, 10.0]), ('Dennis', [90.0, 0.0]), ('Eva', [90.0, 5.0])])

这是关于pyexcel的pe.load和to_dict的文档