[英]How can I put each word of a string into an array in Swift?
是否可以将字符串中的每个单词放入Swift中的数组中?
例如:
var str = "Hello, Playground!"
至:
var arr = ["Hello","Playground"]
谢谢 :)
编辑/更新:
Xcode 10.2•Swift 5或更高版本
我们可以使用集合拆分方法扩展StringProtocol
func split(maxSplits: Int = Int.max, omittingEmptySubsequences: Bool = true, whereSeparator isSeparator: (Character) throws -> Bool) rethrows -> [Self.SubSequence]
将omittingEmptySubsequences
设置为true并将闭包作为谓词传递。 我们还可以利用新的Character
属性isLetter
来分割字符串。
extension StringProtocol {
var words: [SubSequence] {
return split { !$0.isLetter }
}
}
let sentence = "• Hello, Playground!"
let words = sentence.words // ["Hello", "Playground"]
当字符串中有多个连续的空格时,最后一个解决方案(来自Leo)将在数组中创建空元素。 它还将组合以“ - ”分隔的单词和处理行尾字符作为单词。
这个不会:
extension String
{
var wordList: [String]
{
return componentsSeparatedByCharactersInSet(NSCharacterSet.alphanumericCharacterSet().invertedSet).filter({$0 != ""})
}
}
这两个答案目前都不适用于Swift 4,但以下内容可以涵盖OP的问题,希望是你的问题。
extension String {
var wordList: [String] {
return components(separatedBy: CharacterSet.alphanumerics.inverted).filter { !$0.isEmpty }
}
}
let string = "Hello, Playground!"
let stringArray = string.wordList
print(stringArray) // ["Hello", "Playground"]
并且使用带有数字和双倍空格的较长短语:
let biggerString = "Hello, Playground! This is a very long sentence with 123 and other stuff in it"
let biggerStringArray = biggerString.wordList
print(biggerStringArray)
// ["Hello", "Playground", "This", "is", "a", "very", "long", "sentence", "with", "123", "and", "other", "stuff", "in", "it"]
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