如何在python 3.4 tkinter中修复此错误“索引错误：列表索引超出范围”

Question

我正在尝试将一些值和名称保存并加载为小对象，但是在加载部分时遇到了一些麻烦，我正在使用PYTHON 3.4和tkinter创建4个texbox，2个用于名称，2个用于值，以及2个要保存的按钮并加载我在这些文本框上输入的内容，然后我可以在这些文本框中写任何内容，所以可以说我把

苹果20

橙色40

所以在我的前两个文本框中，我在其他两个文本框中有2个字符串和整数
所以我的代码是

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  (NameVal_1, Vol_Val_1,
   NameVal_2, Vol_Val_2)   = (x.split(",")[3] for x in filenamel)

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  file.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

保存正在工作，我可以创建一个显示以下内容的存档.txt

apple,20,orange,40

但是当我尝试将这些值放在文本框中时，我无法使用python说

IndexError: list index out of range

我只想在四个文本框为空并且按下“加载”按钮时，将苹果放在文本框1中，将20放在文本框2中，将橙色放在文本框3中，再将40放在文本框4中。

我该怎么办？ 任何帮助请

EDITED

这是最终代码，谢谢

import time
import serial
import sys
import os
import tkinter as tk
from tkinter import ttk
from tkinter import *
from tkinter import messagebox
from tkinter import filedialog
from tkinter.filedialog import askopenfilename
from tkinter.filedialog import asksaveasfilename
from tkinter.messagebox import showerror
try:
  import Tkinter              # Python 2
  import ttk
except ImportError:
  import tkinter as Tkinter   # Python 3
  import tkinter.ttk as ttk
mGui = Tk()
mGui.title("trying")
mGui.geometry('1250x650+10+10')
def mSave():
  filename = asksaveasfilename(defaultextension='.txt',filetypes = (('Text files', '*.txt'),    ('Python files', '*.py *.pyw'),('All files', '*.*')))
  if filename is None:
    return
  file = open (filename, mode = 'w')
  NameVal_1 = name1.get()
  NameVal_2 = name2.get()
  Vol_Val_1 = value1.get()
  Vol_Val_2 = value2.get()

  all =   (NameVal_1 + "," + (str(Vol_Val_1)) + ","
         + NameVal_2 + "," + (str(Vol_Val_2)))
  file.write(all)
  file.close()

def mLoad():
  filenamel = askopenfilename()
  if filenamel is None:
    return
  with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line
    (NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")  

  name1.set(NameVal_1)
  name2.set(NameVal_2)
  value1.set(Vol_Val_1)
  value2.set(Vol_Val_2)
  filename.close()

value1 = IntVar()
value2 = IntVar()
name1 = StringVar()
name2 = StringVar()

mButtonSave = Button(mGui, text = "Save Data", command = mSave, fg = 'Red').place(x=550,y=80)
mButtonLoad = Button(mGui, text = "Load Data", command = mLoad, fg = 'Red').place(x=550,y=110)

tText1 = Entry(mGui, textvariable = name1).place(x=10,y=80)
tText2 = Entry(mGui, textvariable = name2).place(x=10,y=100)
vText1 = Entry(mGui, textvariable = value1).place(x=200,y=80)
vText2 = Entry(mGui, textvariable = value2).place(x=200,y=100)

Answer 1

filenamel = askopenfilename()仅为您提供文件的路径。 它实际上并不读取文件。 因此，您需要打开它并阅读。 另外，如果文件中只有一行，如您的示例，则此(x.split(",")[3] for x in filenamel) ，因为它遍历(x.split(",")[3] for x in filenamel)路径中的字母而不是行在文件中。 您应该在mLoad()执行以下mLoad() ：

# open the file for reading
with open(filenamel, 'r') as f:
    x = f.readline()  # read the first line   

# split it by ',' and assing to appropriate variables.
(NameVal_1, Vol_Val_1,  NameVal_2, Vol_Val_2) = x.split(",")