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[英]Python process doesn't write stdout to file until execution is finished
[英]Python subprocess doesn't run until calling process finished
编辑1-添加了更多代码,我不确定是否需要proc.communicate,这是我从其他stackoverflow代码中发现的建议之一。(对不起,我昨晚很累,在问这个问题之前并没有想太多)
我应该补充一点,我不是经验丰富的编码员(机械工程师),您可能会从我的代码中看出
在我的Gui中,有一个按钮可以调用子流程
子进程(screenshot-cmd.exe)创建裁剪后的屏幕截图的png,但直到出现错误或按钮单击事件结束后,它才真正生成文件。
这让我认为直到事件结束才真正运行子流程
我想在按下一个按钮后多次调用该过程,并在每次生成后移动它生成的文件
如果我使用proc.wait(),进程将无限期挂起。
如何停止呢?
# function to take a single image called 'fileName' and place it in directory 'dir'
def takeImage(dir,fileName):
# calculate the view to capture to get the whole display window in.
clientRect = win32gui.GetClientRect(win32gui.GetForegroundWindow())
windowRect = win32gui.GetWindowRect(win32gui.GetForegroundWindow())
print(windowRect)
windowSize = [windowRect[2]-windowRect[0],windowRect[3]-windowRect[1]]
print(windowSize)
print(clientRect)
diffSize = [windowSize[0] -clientRect[2], windowSize[1] - clientRect[3]]
lrbBorder = diffSize[0]/2
topBorder = diffSize[1] - lrbBorder
print("sizeDiff = " + str(diffSize))
windowName = win32gui.GetWindowText(win32gui.GetForegroundWindow())
handleId = win32gui.GetForegroundWindow()
leftMar = designLabel.GetPosition()[0] + lrbBorder
topMar = designLabel.GetPosition()[1] + topBorder + designLabel.GetSize()[1]
rightMar = leftMar + scene.width
bottMar = topMar+scene.height
margins = [leftMar,topMar,rightMar,bottMar]
print(margins)
# now print the view.
#command_line = r"screenshot-cmd -wt '" + windowName + "' -rc " + str(margins[0]) + " " + str(margins[1]) + " " + str(margins[2]) + " " + str(margins[3]) + " -o " + fileName
command_line = r"screenshot-cmd -wt '" + windowName + "' -rc " + str(margins[0]) + " " + str(margins[1]) + " " + str(margins[2]) + " " + str(margins[3]) + " -o " + fileName
print(command_line)
args = shlex.split(command_line)
proc = subprocess.Popen(args)
proc.wait()
wx.Yield()
if not os.path.isdir(dir):
os.makedirs(dir)
newPath = os.path.join(dir,fileName)
if os.path.exists(newPath):
os.remove(newPath)
oldPath = os.path.join(os.getcwd(), fileName)
print("Old Path: " + oldPath)
print("Exists: " + str(os.path.exists(oldPath)))
shutil.move(oldPath,newPath)
return
#event called upon clicking 'takeTenImag' button
def takeTenImgE(evt):
global designNo
global workingDirectory
global numDesigns
fileNameRoot = "test_"
fileExtention = ".png"
# check there are at least 10 designs
if numDesigns > 9 and os.path.exists(workingDirectory):
# find directory path to put images in
dir = os.path.join(workingDirectory, "images")
# for each design
for x in range(10):
print("design =" + str(designNo))
fileName = fileNameRoot + str(designNo) + fileExtention
print("------------------")
print("for x = " + str(x) + " " + fileName)
# create image and save
print(dir)
takeImage(dir,fileName)
#move to next design
wx.PostEvent(forwardDesign, wx.CommandEvent(wx.wxEVT_COMMAND_BUTTON_CLICKED, forwardDesign.GetId()) )
wx.Yield()
print("design =" + str(designNo))
return
takeTenImg = wx.Button(p, label='Take Ten Images', pos=(rb + visScaleText.GetSize()[0]+10,takeImg.GetPosition()[1]+5 +takeImg.GetSize()[1]), size = (100,30))
takeTenImg.Bind(wx.EVT_BUTTON, takeTenImgE)
我发现错误在于我对子流程的调用。
我正在使用:
command_line = r"screenshot-cmd -wt '" + windowName + ...."
args = shlex.split(command_line)
subprocess.call(args,shell=True)
更改为:
command_line = r"screenshot-cmd -wt '" + windowName + ...."
subprocess.call(command_line,shell=True)
解决挂起。
奇怪的是,这两个选项均不在wx按钮单击事件(即从命令行启动的python脚本)中起作用,而只有第二个选项在wx按钮单击事件中起作用。 如果有人能启发我,那将是最感激的。
编辑:经进一步调查,挂起是由于尝试在screenshot-cmd中指定活动窗口引起的。
为了解决这个问题,我使用windowRect = win32gui.GetWindowRect(win32gui.GetForegroundWindow())找到了窗口的位置
然后在不指定窗口的情况下使用screenshot-cmd。
尽管尚不清楚这会导致问题的原因,但是这可以解决所有问题
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