如何使用可变函数名称调用standardGeneric

Question

以下代码引发警告：

test_slot = "testslot"

setGeneric(name = test_slot, 
           def = function(object){
               standardGeneric(test_slot)
           },
           where = globalenv()
)



[1] "testslot"
Warning message:
In .recursiveCallTest(body, fname) :
  the body of the generic function for ‘testslot’ calls 'standardGeneric' to dispatch on a different name ("test_slot")!

我希望它等同于：

setGeneric(name = "testslot", 
           def = function(object){
               standardGeneric("testslot")
           },
           where = globalenv()
)

发生了什么？

Answer 1

这不能回答为什么原始代码块失败的原因，但是可以采用以下解决方法：

test_slot = "testslot"

setGeneric(name = test_slot, 
           def = eval(parse(text = paste0("function(object){",

           "standardGeneric('", test_slot, "')",
       "}")))
           },
           where = globalenv()
)

也就是说，将整个def参数构造为一个求值函数。