使用Python将超链接插入到Excel中的本地文件夹

Question

该段代码读取一个Excel文件。 此excel文件包含诸如客户职位编号，客户名称，站点，作品说明等信息。

这段代码完成后会做什么（我希望）是读取工作表的最后一行（这是从工作表上“ P1”单元格的计数器中提取的），根据单元格内容创建文件夹，并在工作表上创建超链接打开创建的最低本地文件夹。

我已经从工作表中提取了我需要的信息，以了解需要创建哪些文件夹，但是我无法在B列中的行上的单元格中写入超链接。

#Insert Hyperlink to folder
def folder_hyperlink(last_row_position, destination):
    cols = 'B'
    rows = str(last_row_position)
    position = cols + rows
    final_position = "".join(position)
    print final_position # This is just to check the value
    # The statement below should insert hyperlink in eps.xlsm > worksheet jobnoeps at column B and last completed row.
    ws.cell(final_position).hyperlink = destination

完整的代码在下面，但此处是用于创建超链接的部分。 我也没有高兴地尝试过“ xlswriter”软件包。 搜索了互联网，上面的代码段是我发现的结果。

有人知道我在做什么错吗？

 __author__ = 'Paul'

import os
import openpyxl
from openpyxl import load_workbook
import xlsxwriter

site_info_root = 'C:\\Users\\paul.EPSCONSTRUCTION\\PycharmProjects\\Excel_Jobs\\Site Information\\'

# This function returns the last row on eps.xlsm to be populated
def get_last_row(cell_ref = 'P1'): #P1 contains the count of the used rows
    global wb
    global ws
    wb = load_workbook("eps.xlsm", data_only = True) #Workbook
    ws = wb["jobnoeps"] #Worksheet
    last_row = ws.cell(cell_ref).value #Value of P1 from that worksheet
    return last_row


# This function will read the job number in format EPS-XXXX-YR
def read_last_row_jobno(last_row_position):
    last_row_data = []
    for cols in range(1, 5):
        last_row_data += str(ws.cell(column = cols, row = last_row_position).value)
    last_row_data_all = "".join(last_row_data)
    return last_row_data_all


#This function will return the Customer
def read_last_row_cust(last_row_position):
    cols = 5
    customer_name = str(ws.cell(column = cols, row = last_row_position).value)
    return customer_name


#This function will return the Site
def read_last_row_site(last_row_position):
    cols = 6
    site_name = str(ws.cell(column = cols, row = last_row_position).value)
    return site_name


#This function will return the Job Discription
def read_last_row_disc(last_row_position):
    cols = 7
    site_disc = str(ws.cell(column = cols, row = last_row_position).value)
    return site_disc


last_row = get_last_row()
job_no_details = read_last_row_jobno(last_row)
job_customer = read_last_row_cust(last_row)
job_site = read_last_row_site(last_row)
job_disc = read_last_row_disc(last_row)

cust_folder = job_customer
job_dir = job_no_details + "\\" + job_site + " - " + job_disc


#Insert Hyperlink to folder
def folder_hyperlink(last_row_position, destination):
    cols = 'B'
    rows = str(last_row_position)
    position = cols + rows
    final_position = "".join(position)
    print final_position # This is just to check the value
    # The statement below should insert hyperlink in eps.xlsm > worksheet jobnoeps at column B and last completed row.
    ws.cell(final_position).hyperlink = destination



folder_location = site_info_root + job_customer + "\\" + job_dir


print folder_location # This is just to check the value
folder_hyperlink(last_row, folder_location)

---

现在，按照建议尝试xlsxwriter后，我的超链接功能如下所示。

##Insert Hyperlink to folder
def folder_hyperlink(last_row_position, destination):
    import xlsxwriter
    cols = 'B'
    rows = str(last_row_position)
    position = cols + rows
    final_position = "".join(position)
    print final_position # This is just to check the value
    workbook = xlsxwriter.Workbook('eps.xlsx')
    worksheet = workbook.add_worksheet('jobnoeps')
    print worksheet
    worksheet.write_url(final_position, 'folder_location')
    workbook.close()

该函数将覆盖现有的eps.xlsx，创建一个作业表，然后插入超链接。 我玩过以下几行，但不知道如何打开现有的xlsx和现有的jobnoeps选项卡，然后输入超链接。

workbook = xlsxwriter.Workbook('eps.xlsx')
worksheet = workbook.add_worksheet('jobnoeps')
worksheet.write_url(final_position, 'folder_location')

Answer 1

XlsxWriter write_url()方法允许您链接到文件夹或其他工作簿和工作表，以及内部链接和Web url的链接。 例如：

import xlsxwriter

workbook = xlsxwriter.Workbook('links.xlsx')
worksheet = workbook.add_worksheet()

worksheet.set_column('A:A', 50)

# Link to a Folder.
worksheet.write_url('A1', r'external:C:\Temp')

# Link to a workbook.
worksheet.write_url('A3', r'external:C:\Temp\Book.xlsx')

# Link to a cell in a worksheet.
worksheet.write_url('A5', r'external:C:\Temp\Book.xlsx#Sheet1!C5')

workbook.close()

有关更多详细信息，请参见上面链接的文档。

Answer 2

这是完成窍门的代码：

# Creates hyperlink in existing workbook...

def set_hyperlink():
    from openpyxl import load_workbook
    x = "hyperlink address"
    wb = load_workbook("filename.xlsx")
    ws = wb.get_sheet_by_name("sheet_name")
    ws.cell(row = x?, column = y?).hyperlink = x
    wb.save("filename.xlsx")

set_hyperlink()

按照建议再次与openpyxl一起尝试。