如何找到文件，然后在Python中循环遍历它们？

Question

我有一个包含以下代码的Bash脚本：

merge_ROOT_files(){
    output_file=""$(date -u "+%Y-%m-%dT%H%M%S")"Z_merged.root"
    list_of_files="$(find . -name \*.root -type f)"
    command="hadd "${output_file}""
    for current_file in ${list_of_files}; do
        echo "found ROOT file "${current_file}""
        command=""${command}" "${current_file}""
    done
    echo "merge ROOT files to output ROOT file "${output_file}""
    echo "merge command: ${command}"
    eval "${command}"
}

merge_ROOT_files

您可以看到它以递归方式搜索以.root结尾的文件，然后循环遍历这些文件。 如何在Python中做类似的事情？ 我可以想象生成各种找到的文件及其完整或相对路径的列表，然后遍历该列表，但是我不确定如何生成这样的列表。

Answer 1

这里有一些代码应该可以帮助您。

import os
import re

searchdir = '.'
ext_rx = '\.root$'

filelist = []

for root, dir, files in os.walk(searchdir):
    for file in files:
        if re.search(ext_rx, file):
            filelist.append(os.path.join(root, file))

for file in filelist:
    print(file)

Answer 2

glob使执行此类操作变得非常容易。

import os
import glob

# Get full path for .root files
root_files = glob.glob('/your_path/*.root')

# Only get root file names
root_file_names = [os.path.basename(f) for f in glob.iglob('/your_path/*.root')]

Answer 3

考察os.walk

这对于梳理文件系统非常有用

http://www.tutorialspoint.com/python/os_walk.htm

Answer 4

我已提取的代码从我的常用utils

import os
import os.path

def flatten( seq ) :
  res = []
  for item in seq :
    if ( isinstance( item, ( tuple, list ) ) ) :
      res.extend( flatten( item ) )
    else:
      res.append( item )
  return res


def get_roots( path ) :
    """Get a list of .root files in a given directory.
    """
    rootfiles2 = []
    os.listdir( path )
    for root, dirs, files in os.walk( path, topdown=True ) :
        #print ( 'root =', root, ', dirs =', dirs, ', files =', files )
        print ( 'root =', root )
        print ( 'dirs =', dirs )
        print ( 'files =', files )
        # Get only .root files
        rootfiles2.append( [ root + '/' + file for file in files if ( file.split('.')[-1] == 'root' ) ] )
    rootfiles = list( flatten( rootfiles2 ) )
    return rootfiles

Answer 5

这是我的处理方式：

import os
import fnmatch
import subprocess
import datetime


def merge_ROOT_files():
    output_file = datetime.datetime.utcnow().strftime("%Y-%m-%dT%H%M%SZ_merged.root")

    root_files = [
        os.path.join(root, filename)
        for root, dirs, files in os.walk('.')
        for filename in files
        if fnmatch.fnmatch(filename, '*.root')
    ]

    # Remove 'echo' when you want to go live.
    subprocess.check_call(['echo', 'hadd', output_file]+root_files)

if __name__ == "__main__":
    merge_ROOT_files()