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Python 分别从子进程 stdout 和 stderr 读取,同时保留顺序

[英]Python read from subprocess stdout and stderr separately while preserving order

我有一个 python 子进程,我试图从中读取输出和错误流。 目前我可以使用它,但是我只能在完成从stdout读取后才能从stderr读取。 这是它的样子:

process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout_iterator = iter(process.stdout.readline, b"")
stderr_iterator = iter(process.stderr.readline, b"")

for line in stdout_iterator:
    # Do stuff with line
    print line

for line in stderr_iterator:
    # Do stuff with line
    print line

如您所见, stderr for 循环在stdout循环完成之前无法启动。 如何修改它以便能够以正确的顺序读取行进来的两者?

澄清一下我仍然需要能够判断一行是来自stdout还是stderr因为它们在我的代码中将被区别对待。

如果子进程在 stderr 上产生足够的输出(在我的 Linux 机器上约为 100KB),那么您问题中的代码可能会死锁。

有一个communicate()方法允许分别从 stdout 和 stderr 读取:

from subprocess import Popen, PIPE

process = Popen(command, stdout=PIPE, stderr=PIPE)
output, err = process.communicate()

如果您需要在子进程仍在运行时读取流,那么可移植的解决方案是使用线程(未测试):

from subprocess import Popen, PIPE
from threading import Thread
from Queue import Queue # Python 2

def reader(pipe, queue):
    try:
        with pipe:
            for line in iter(pipe.readline, b''):
                queue.put((pipe, line))
    finally:
        queue.put(None)

process = Popen(command, stdout=PIPE, stderr=PIPE, bufsize=1)
q = Queue()
Thread(target=reader, args=[process.stdout, q]).start()
Thread(target=reader, args=[process.stderr, q]).start()
for _ in range(2):
    for source, line in iter(q.get, None):
        print "%s: %s" % (source, line),

看:

这是一个基于selectors的解决方案,但它保留了顺序,并流式传输可变长度字符(甚至单个字符)。

诀窍是使用read1() ,而不是read()

import selectors
import subprocess
import sys

p = subprocess.Popen(
    ["python", "random_out.py"], stdout=subprocess.PIPE, stderr=subprocess.PIPE
)

sel = selectors.DefaultSelector()
sel.register(p.stdout, selectors.EVENT_READ)
sel.register(p.stderr, selectors.EVENT_READ)

while True:
    for key, _ in sel.select():
        data = key.fileobj.read1().decode()
        if not data:
            exit()
        if key.fileobj is p.stdout:
            print(data, end="")
        else:
            print(data, end="", file=sys.stderr)

如果您想要一个测试程序,请使用它。

import sys
from time import sleep


for i in range(10):
    print(f" x{i} ", file=sys.stderr, end="")
    sleep(0.1)
    print(f" y{i} ", end="")
    sleep(0.1)

进程将数据写入不同管道的顺序在写入后丢失。

您无法判断 stdout 是否已在 stderr 之前写入。

一旦数据可用,您可以尝试以非阻塞方式同时从多个文件描述符中读取数据,但这只会最大限度地减少顺序不正确的可能性。

这个程序应该证明这一点:

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import os
import select
import subprocess

testapps={
    'slow': '''
import os
import time
os.write(1, 'aaa')
time.sleep(0.01)
os.write(2, 'bbb')
time.sleep(0.01)
os.write(1, 'ccc')
''',
    'fast': '''
import os
os.write(1, 'aaa')
os.write(2, 'bbb')
os.write(1, 'ccc')
''',
    'fast2': '''
import os
os.write(1, 'aaa')
os.write(2, 'bbbbbbbbbbbbbbb')
os.write(1, 'ccc')
'''
}

def readfds(fds, maxread):
    while True:
        fdsin, _, _ = select.select(fds,[],[])
        for fd in fdsin:
            s = os.read(fd, maxread)
            if len(s) == 0:
                fds.remove(fd)
                continue
            yield fd, s
        if fds == []:
            break

def readfromapp(app, rounds=10, maxread=1024):
    f=open('testapp.py', 'w')
    f.write(testapps[app])
    f.close()

    results={}
    for i in range(0, rounds):
        p = subprocess.Popen(['python', 'testapp.py'], stdout=subprocess.PIPE
                                                     , stderr=subprocess.PIPE)
        data=''
        for (fd, s) in readfds([p.stdout.fileno(), p.stderr.fileno()], maxread):
            data = data + s
        results[data] = results[data] + 1 if data in results else 1

    print 'running %i rounds %s with maxread=%i' % (rounds, app, maxread)
    results = sorted(results.items(), key=lambda (k,v): k, reverse=False)
    for data, count in results:
        print '%03i x %s' % (count, data)


print
print "=> if output is produced slowly this should work as whished"
print "   and should return: aaabbbccc"
readfromapp('slow',  rounds=100, maxread=1024)

print
print "=> now mostly aaacccbbb is returnd, not as it should be"
readfromapp('fast',  rounds=100, maxread=1024)

print
print "=> you could try to read data one by one, and return"
print "   e.g. a whole line only when LF is read"
print "   (b's should be finished before c's)"
readfromapp('fast',  rounds=100, maxread=1)

print
print "=> but even this won't work ..."
readfromapp('fast2', rounds=100, maxread=1)

并输出如下内容:

=> if output is produced slowly this should work as whished
   and should return: aaabbbccc
running 100 rounds slow with maxread=1024
100 x aaabbbccc

=> now mostly aaacccbbb is returnd, not as it should be
running 100 rounds fast with maxread=1024
006 x aaabbbccc
094 x aaacccbbb

=> you could try to read data one by one, and return
   e.g. a whole line only when LF is read
   (b's should be finished before c's)
running 100 rounds fast with maxread=1
003 x aaabbbccc
003 x aababcbcc
094 x abababccc

=> but even this won't work ...
running 100 rounds fast2 with maxread=1
003 x aaabbbbbbbbbbbbbbbccc
001 x aaacbcbcbbbbbbbbbbbbb
008 x aababcbcbcbbbbbbbbbbb
088 x abababcbcbcbbbbbbbbbb

这适用于 Python3 (3.6):

    p = subprocess.Popen(cmd, stdout=subprocess.PIPE, 
                         stderr=subprocess.PIPE, universal_newlines=True)
    # Read both stdout and stderr simultaneously
    sel = selectors.DefaultSelector()
    sel.register(p.stdout, selectors.EVENT_READ)
    sel.register(p.stderr, selectors.EVENT_READ)
    ok = True
    while ok:
        for key, val1 in sel.select():
            line = key.fileobj.readline()
            if not line:
                ok = False
                break
            if key.fileobj is p.stdout:
                print(f"STDOUT: {line}", end="")
            else:
                print(f"STDERR: {line}", end="", file=sys.stderr)

来自https://docs.python.org/3/library/subprocess.html#using-the-subprocess-module

如果您希望捕获两个流并将其合并为一个,请使用 stdout=PIPE 和 stderr=STDOUT 而不是 capture_output。

所以最简单的解决方案是:

process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
stdout_iterator = iter(process.stdout.readline, b"")

for line in stdout_iterator:
    # Do stuff with line
    print line

我有一个python子进程,我正在尝试从中读取输出和错误流。 目前,我已经可以使用它了,但是只有从stdout读取完之后,我才能从stderr读取内容。 看起来是这样的:

process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout_iterator = iter(process.stdout.readline, b"")
stderr_iterator = iter(process.stderr.readline, b"")

for line in stdout_iterator:
    # Do stuff with line
    print line

for line in stderr_iterator:
    # Do stuff with line
    print line

如您所见, stderr for循环在stdout循环完成之前无法启动。 我如何修改它以便能够以正确的顺序从行中读取两者?

需要说明的是:我仍然需要能够分辨出一行是来自stdout还是stderr因为它们在我的代码中将被区别对待。

我知道这个问题很老了,但是这个答案可能会帮助偶然发现此页面的其他人研究类似情况的解决方案,所以我还是发布了它。

我已经构建了一个简单的 python 片段,它将任意数量的管道合并为一个。 当然,如上所述,顺序不能保证,但这与我认为您在 Python 中所能获得的最接近。

它为每个管道生成一个线程,逐行读取它们并将它们放入队列(即 FIFO)。 主线程循环遍历队列,产生每一行。

import threading, queue
def merge_pipes(**named_pipes):
    r'''
    Merges multiple pipes from subprocess.Popen (maybe other sources as well).
    The keyword argument keys will be used in the output to identify the source
    of the line.

    Example:
    p = subprocess.Popen(['some', 'call'],
                         stdin=subprocess.PIPE,
                         stdout=subprocess.PIPE,
                         stderr=subprocess.PIPE)
    outputs = {'out': log.info, 'err': log.warn}
    for name, line in merge_pipes(out=p.stdout, err=p.stderr):
        outputs[name](line)

    This will output stdout to the info logger, and stderr to the warning logger
    '''

    # Constants. Could also be placed outside of the method. I just put them here
    # so the method is fully self-contained
    PIPE_OPENED=1
    PIPE_OUTPUT=2
    PIPE_CLOSED=3

    # Create a queue where the pipes will be read into
    output = queue.Queue()

    # This method is the run body for the threads that are instatiated below
    # This could be easily rewritten to be outside of the merge_pipes method,
    # but to make it fully self-contained I put it here
    def pipe_reader(name, pipe):
        r"""
        reads a single pipe into the queue
        """
        output.put( ( PIPE_OPENED, name, ) )
        try:
            for line in iter(pipe.readline,''):
                output.put( ( PIPE_OUTPUT, name, line.rstrip(), ) )
        finally:
            output.put( ( PIPE_CLOSED, name, ) )

    # Start a reader for each pipe
    for name, pipe in named_pipes.items():
        t=threading.Thread(target=pipe_reader, args=(name, pipe, ))
        t.daemon = True
        t.start()

    # Use a counter to determine how many pipes are left open.
    # If all are closed, we can return
    pipe_count = 0

    # Read the queue in order, blocking if there's no data
    for data in iter(output.get,''):
        code=data[0]
        if code == PIPE_OPENED:
            pipe_count += 1
        elif code == PIPE_CLOSED:
            pipe_count -= 1
        elif code == PIPE_OUTPUT:
            yield data[1:]
        if pipe_count == 0:
            return

这对我有用(在 Windows 上): https : //github.com/waszil/subpiper

from subpiper import subpiper

def my_stdout_callback(line: str):
    print(f'STDOUT: {line}')

def my_stderr_callback(line: str):
    print(f'STDERR: {line}')

my_additional_path_list = [r'c:\important_location']

retcode = subpiper(cmd='echo magic',
                   stdout_callback=my_stdout_callback,
                   stderr_callback=my_stderr_callback,
                   add_path_list=my_additional_path_list)

我有一个python子进程,我正在尝试从中读取输出和错误流。 目前,我已经可以使用它了,但是只有从stdout读取完之后,我才能从stderr读取内容。 看起来是这样的:

process = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
stdout_iterator = iter(process.stdout.readline, b"")
stderr_iterator = iter(process.stderr.readline, b"")

for line in stdout_iterator:
    # Do stuff with line
    print line

for line in stderr_iterator:
    # Do stuff with line
    print line

如您所见, stderr for循环在stdout循环完成之前无法启动。 我如何修改它以便能够以正确的顺序从行中读取两者?

需要说明的是:我仍然需要能够分辨出一行是来自stdout还是stderr因为它们在我的代码中将被区别对待。

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