[英]reading last line of txt file in python and change it into variable to make calculation
td = 'date of transaction.txt'
tf = 'current balance.txt'
tr = 'transaction record.txt'
for line in open(tf):pass
for line2 in open(td):pass
for line3 in open(tr):pass
print line2,line,line3
"""
so call recall back last record
"""
rd=raw_input('\ndate of transaction: ')
print "Choose a type of transaction to proceed... \n\tA.Withdrawal \n\tB.Deposit \n\tC.Cancel & exit"
slc=raw_input('type of transaction: ')
i=1
while (i>0):
if slc=="A" or slc=="B" or slc=="C":
i=0
else:
i=i+1
slc=raw_input('invalid selection, please choose again...(A/B/C): ')
if slc=="A":
rr=input('\namount of transaction: ')
Line_len = 10 # or however long a line is, since in my example they all looked the same
SEEK_END = 2
file = open(tf, "r")
file.seek(-Line_len, SEEK_END)
a = int(str(file.read(Line_len)).split(" ")[0].strip())
rf=a-rr
f1=open(tf, 'a+')
f1.write('\n'+rf)
f1.close()
d1=open(td, 'a+')
d1.write('\n'+rd)
d1.close
r1=open(tr, 'a+')
r1.write('\n-'+rr)
r1.close
else:
print 'later'
上面是我的代码,功能是从txt文件获取数据(最后一行)并读取它,获取新数据,然后通过创建新行将其再次写入txt文件。 我的txt文件(当前balance.txt)应如下所示:
2894.00
2694.00
但是当我尝试使用2694.00的最后一行进行计算(rf = a-rr)时,返回此错误失败:
Traceback (most recent call last):
File "C:\Python27\acc.py", line 27, in <module>
file.seek(-Line_len, SEEK_END)
IOError: [Errno 22] Invalid argument
否则,如果我使用此代码:
for line in open(tf):
pass
a = line
rf=a-rr
它返回此错误:
Traceback (most recent call last):
File "C:\Python27\acc.py", line 27, in <module>
rf=a-rr
TypeError: unsupported operand type(s) for -: 'str' and 'int'
我真的不知道为什么...请帮助我...
要获取文件的最后一行,您可以简单地执行
with open('my_file.txt') as file:
last_line = file.readlines()[-1]
#last_line is a string value pointing to last line, to convert it into float, you can do
number = float(last_line.strip('\n').strip(' '))
函数输入为您提供了一个字符串。 尝试做:
rf=a-float(rr)
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