Python使用命名空间的等价性

Question

我有以下Helper.py python脚本

class Helper:
# Helper has many many classes! (AA, BB, CC, DD, ....) not just 2!
    class AA:
        CMD_AA = '8'
        CMD_AB = '1'

    class BB:
        CMD_BA = '0'
        CMD_BB = '1'

我创建了这个帮助文件，使代码更具可读性。 所以可以写这个;

# this usage is more readable and makes sense
cmd.a = AA.CMD_AB 
cmd.b = BB.CMD_BB 

# instead of some thing like this where no one knows
# what 1 is interms of a or b!!
cmd.a = 1
cmd.b = 1

辅助脚本在许多python文件中导入！ 我知道如何使用它的唯一方法就是这样

from Helper import *
cmd.a = Helper.AA.CMD_AA  # instead of cmd.a = 8
cmd.b = Helper.BB.CMD_BB  # instead of cmd.b = 1

有没有办法摆脱'助手'。 我已经添加了更多打字。 所以它看起来像;

from Helper import *

#in C++ u can use something like using namespace Helper;
cmd.a = AA.CMD_AA  # instead of cmd.a = 8
cmd.b = BB.CMD_BB  # instead of cmd.b = 1

Answer 1

你应该只删除包装器Helper类并对文件的其余部分进行删除...如果你需要，文件本身就会提供命名空间

Helper.py

class CMD_AA:
    ...

main.py

import Helper
Helper.CMD_AA
# or just
from Helper import CMD_AA