python骰子游戏中的语法错误

Question

我有一个语法错误，无法弄清楚出了什么问题有人可以帮忙

    import random

play=input("would you like to play Y/N")

if play==Y:
    dice_roll
if play==N:
    print("try again")
    play=input("would you like to play Y/N")

#declare dice as global and rolls dice 
def dice_roll():
    global p1_dice_1
    global p1_dice_2
    global p1_dice_3
    global p2_dice_1
    global p2_dice_2
    global p2_dice_3
    p1_dice_1=random.randint(1,6)
    p1_dice_2=random.randint(1,6)
    p1_dice_3=random.randint(1,6)
    p2_dice_1=random.randint(1,6)
    p2_dice_2=random.randint(1,6)
    p2_dice_3=random.randint(1,6)
    print_test()
    return

def print_test():
    print("player 1 rolled",p1_dice_1,",",p1_dice_2,"and",p1_dice_3)
    print("palyer 2 rolled",p2_dice_1,",",p2_dice_2,"and",p2_dice_3)
    score_rule()
    return

如果这可以变得不那么复杂，我不介意帮助

 score_rule():
        if p1_dice_1==p1_dice_2==p1_dice_3:
            print("player 1 scored",p1_dice_1+p1_dice_2+p1_dice_3)
        elif p1_dice_1==p1_dice_2=!p1_dice_3:
            print("player 1 scored",p1_dice_1+p1_dice_2-p1_dice_3)
        elif p1_dice_1==p1_dice_3=!p1_dice_2:
            print("player 1 scored",p1_dice_1+p1_dice_3-p1_dice_2)
        elif p1_dice_2==p1_dice_3=!p1_dice_1:
            print("player 1 scored",p1_dice_2+p1_dice_3-p1_dice_1)

    if p2_dice_1==p2_dice_2==p2_dice_3:
        print("player 2 scored",p2_dice_1+p2_dice_2+p2_dice_3)
    elif p2_dice_1==p2_dice_2=!p2_dice_3:
        print("player 2 scored",p2_dice_1+p2_dice_2-p2_dice_3)
    elif p2_dice_1==p2_dice_3=!p2_dice_2:
        print("player 2 scored",p2_dice_1+p2_dice_3-p2_dice_2)
    elif p2_dice_2==p2_dice_3=!p2_dice_1:
        print("player 2 scored",p2_dice_2+p2_dice_3-p2_dice_1)
    return

如果有人知道该怎么做帮助，我不得不在问题中添加更多词，因为代码太多（显然）

Answer 1

• import random缩进不正确。
• score_rule的主体缩进不一致。
• score_rule():应该是def score_rule():
• “=！” 不是合法经营者。 使用“！=”。
• Y和N没有定义。 使用字符串文字。
• dice_roll需要在引用之前定义。 移动您的主代码，使其出现在您的函数定义之后。
• 函数调用需要括号。 更改dice_roll到dice_roll()

import random

#declare dice as global and rolls dice 
def dice_roll():
    global p1_dice_1
    global p1_dice_2
    global p1_dice_3
    global p2_dice_1
    global p2_dice_2
    global p2_dice_3
    p1_dice_1=random.randint(1,6)
    p1_dice_2=random.randint(1,6)
    p1_dice_3=random.randint(1,6)
    p2_dice_1=random.randint(1,6)
    p2_dice_2=random.randint(1,6)
    p2_dice_3=random.randint(1,6)
    print_test()
    return

def print_test():
    print("player 1 rolled",p1_dice_1,",",p1_dice_2,"and",p1_dice_3)
    print("palyer 2 rolled",p2_dice_1,",",p2_dice_2,"and",p2_dice_3)
    score_rule()
    return

def score_rule():
    if p1_dice_1==p1_dice_2==p1_dice_3:
        print("player 1 scored",p1_dice_1+p1_dice_2+p1_dice_3)
    elif p1_dice_1==p1_dice_2!=p1_dice_3:
        print("player 1 scored",p1_dice_1+p1_dice_2-p1_dice_3)
    elif p1_dice_1==p1_dice_3!=p1_dice_2:
        print("player 1 scored",p1_dice_1+p1_dice_3-p1_dice_2)
    elif p1_dice_2==p1_dice_3!=p1_dice_1:
        print("player 1 scored",p1_dice_2+p1_dice_3-p1_dice_1)

    if p2_dice_1==p2_dice_2==p2_dice_3:
        print("player 2 scored",p2_dice_1+p2_dice_2+p2_dice_3)
    elif p2_dice_1==p2_dice_2!=p2_dice_3:
        print("player 2 scored",p2_dice_1+p2_dice_2-p2_dice_3)
    elif p2_dice_1==p2_dice_3!=p2_dice_2:
        print("player 2 scored",p2_dice_1+p2_dice_3-p2_dice_2)
    elif p2_dice_2==p2_dice_3!=p2_dice_1:
        print("player 2 scored",p2_dice_2+p2_dice_3-p2_dice_1)
    return

play=input("would you like to play Y/N")

if play=='Y':
    dice_roll()
if play=='N':
    print("try again")
    play=input("would you like to play Y/N")

结果：

would you like to play Y/NY
player 1 rolled 6 , 4 and 5
palyer 2 rolled 3 , 4 and 6

您可能还需要额外的else子句，当没有两个骰子相等时，这些子句会得分。

Answer 2

查看错误消息会很有用

但如果那是您的代码，请尝试

if play=='Y':

'N' 语句类似。

编辑：答案 2 也是有效的，dice_roll 是一个函数，dice_roll()。

再次编辑：有人回来了一个非常全面的答案，参考他的。