列表上不同点的距离

Question

您好，我是python新手，

我试图找到不同点之间的距离。 例：

每扇门之间的距离约为2.5英尺。 因此，门1和门2之间的距离为2.5英尺。 我将如何在门字典中查找两个不同的距离。 还是我应该使用其他东西。

d = {"door 1" : 2.5,"door 2" :2.5 , "door 3" : 2.5, "door 4": 2.5}

x = raw_input()
y = raw_input()
tol = 0


if x not in list and y not in list:
        print 'not a door'

else:
    if x in list and y in list:
        tol = (list[x]) + (list[y])
        print tol

Answer 1

会用一个函数做到这一点。 这里是一个示例：

# FUNTION
def calDoorDistance(doorX, doorY):
    # Distance between doors
    distance = 2.5

    # Splits the input string by spaces
    # gets the last portion of it
    # and converts it to integers
    door_01_value = int(doorX.split(' ')[-1])
    door_02_value = int(doorY.split(' ')[-1])

    # Calculates the amount of doors in between
    # and multiplies it by the distance.
    # abs makes sure that the result is always positive
    return abs(door_01_value - door_02_value) * distance

    x = raw_input()  # Converts the input value into an integer
    y = raw_input()  # Converts the input value into an integer

print calDoorDistance(x, y)

Answer 2

您可以尝试以下方法。 假设您所有的门都间隔2.5并成一直线：

valid_doors = {"door 1" : 1.0, "door 2" : 2.0, "door 3" : 3.0, "door 4": 4.0}

x = raw_input("Enter first door: ")
y = raw_input("Enter second door: ")

if x in valid_doors and y in valid_doors:
    print abs(valid_doors[x] - valid_doors[y]) * 2.5
else:
    print 'not a door'

这将为您提供以下输出：

Enter first door: door 1
Enter second door: door 2
2.5

Enter first door: door 4
Enter second door: door 2
5.0

或者，稍微多一点Python风格，您可以了解如下有关感知处理的信息：

valid_doors = {"door 1" : 1.0, "door 2" : 2.0, "door 3" : 3.0, "door 4": 4.0}

x = raw_input("Enter first door: ")
y = raw_input("Enter second door: ")

try:
    print abs(valid_doors[x] - valid_doors[y]) * 2.5
except KeyError:
    print 'not a door'