我正在尝试用python编写数字猜谜游戏，但我的程序无法正常工作

Question

该程序应该随机生成一个介于1到10（含）之间的数字，并要求用户猜测该数字。 如果他们弄错了，他们可以再次猜测，直到正确为止。 如果他们猜对了，该程序应该向他们表示祝贺。

这是我所拥有的，它不起作用。 我输入的数字介于1到10之间，没有任何祝贺。 当我输入一个负数时，什么也没有发生。

import random


number = random.randint(1,10)

print "The computer will generate a random number between 1 and 10. Try  to guess the number!"

guess = int(raw_input("Guess a number: "))


while guess != number:
    if guess >= 1 and guess <= 10:
       print "Sorry, you are wrong."
       guess = int(raw_input("Guess another number: ")) 
   elif guess <= 0 and guess >= 11: 
      print "That is not an integer between 1 and 10 (inclusive)."
      guess = int(raw_input("Guess another number: "))
   elif guess == number:
     print "Congratulations! You guessed correctly!"

Answer 1

只需将祝贺消息移到循环外即可。 然后，循环中也只能有一个猜测输入。 以下应该工作：

while guess != number:
    if guess >= 1 and guess <= 10:
        print "Sorry, you are wrong."
    else:
        print "That is not an integer between 1 and 10 (inclusive)."

    guess = int(raw_input("Guess another number: "))

print "Congratulations! You guessed correctly!"

Answer 2

问题是在if / elif链中，它从上到下对其进行评估。 向上移动最后一个条件。

if guess == number:
   ..
elif other conditions.

另外，您需要更改while循环以允许它在第一次进入。 例如。

while True:
 guess = int(raw_input("Guess a number: "))
 if guess == number:
   ..

然后在您有条件结束游戏时休息。

Answer 3

问题是，如果正确猜测的条件为true，则退出while循环。 我建议解决此问题的方法是将祝贺移到while循环之外

import random


number = random.randint(1,10)

print "The computer will generate a random number between 1 and 10.   Try  to guess the number!"

guess = int(raw_input("Guess a number: "))


while guess != number:
    if guess >= 1 and guess <= 10:
       print "Sorry, you are wrong."
       guess = int(raw_input("Guess another number: ")) 
    elif guess <= 0 and guess >= 11: 
       print "That is not an integer between 1 and 10 (inclusive)."
       guess = int(raw_input("Guess another number: "))

if guess == number:
 print "Congratulations! You guessed correctly!"