如何通过使用列表的索引作为键和列表的项作为值来将列表添加到字典？

Question

问：给定一个list命名list1和字典命名dict1 ，使用“for”循环编写代码来添加的所有项目list1至dict1使用的索引list作为字典的关键和的项目list作为字典的值。 例如：

`    list1 = ["a","b","c"]`

`    dict1 = {7:"d",8:"e",9:"f"}`

运行代码后， dict1 = {7:"d",8:"e",9:"f",0:"a",1:"b",2:"c"}

我的代码：

`dict1 = {7:"d", 8:"e", 9:"f"}
list1 = ["a", "b", "c"]
ii = 0
for i in [dict1]:
    dict1[ii] = list1[ii]
    ii = ii + 1
    print(dict1)`

经过1个绝望小时的尝试：

`for i in list1:
    if i not in dict1.keys():
        dict1[0] = list1[0]
        dict1[1] = list1[1]
        dict1[2] = list1[2] 
        print(dict1)`

我迷路了！

Answer 1

这样吧

>>> list1 = ["a","b","c"]
>>> dict1 = {7:"d",8:"e",9:"f"}
>>> dict1.update(dict(enumerate(list1)))
>>> dict1
{0: 'a', 1: 'b', 2: 'c', 7: 'd', 8: 'e', 9: 'f'}

要么

>>> dict(dict1.items() + list(enumerate(list1)))
{0: 'a', 1: 'b', 2: 'c', 7: 'd', 8: 'e', 9: 'f'}