如何随机化repeatAction计数？

Question

我有一个永远重复的SKAction，它会在wave中释放一个随机数量的对象但是我似乎无法在SKAction.repeatActionForver中重复每次重复SKAction.repeatAction的计数。 有人知道我的问题的解决方案吗？

let objectSet = SKAction.repeatAction（SKAction.sequence（[addObject，objectDelay]），count： random value ））

let setDelay = SKAction.waitForDuration(2.0, withRange: 1.0)

let objectDelay = SKAction.waitForDuration(0.6, withRange: 0.4)

let objectSet = SKAction.repeatAction(SKAction.sequence([addObject, objectDelay]), count: *Trying to get a random value*))

objectLayerNode.runAction(SKAction.repeatActionForever(SKAction.sequence([objectSet, setDelay])))

谢谢

Answer 1

您可以使用let random = Int(arc4random_uniform(UPPER_BOUND)) 。

然后

let objectSet = SKAction.repeatAction(SKAction.sequence([addObject, objectDelay]), count: random))

您还可以执行具有上限和下限的范围。

let random = LOWER_BOUND + arc4random_uniform(UPPER_BOUND - LOWER_BOUND + 1)

编辑

你可以使用递归。 参考

let setDelay = SKAction.waitForDuration(2.0, withRange: 1.0)
let objectDelay = SKAction.waitForDuration(0.6, withRange: 0.4)

func repeat() {

    let random = LOWER_BOUND + arc4random_uniform(UPPER_BOUND - LOWER_BOUND + 1)

    let objectSet = SKAction.repeatAction(SKAction.sequence([addObject, objectDelay]), count: random))

    let sequence = SKAction.sequence([
        objectSet, objectDelay,SKAction.runBlock({
            [unowned self] in self.repeat()
        })
    ])

    objectLayerNode.runAction(sequence)
}