Unity Timer变为负数？

Question

因此，我正在尝试为我的游戏制作一个“商人”系统。 5分钟后（计时器在滴答声中），商家将可用，第二个计时器将开始滴答，但第二个计时器在-中。

    void Update()
{
    timeremaining -= Time.deltaTime;
    int minutes = Mathf.FloorToInt(timeremaining / 60F);
    int seconds = Mathf.FloorToInt(timeremaining - minutes * 60);
    string niceTime = string.Format("{0:0}:{1:00}", minutes, seconds);

    howlonghere -= Time.deltaTime;
    int minutes2 = Mathf.FloorToInt(howlonghere / 60F);
    int seconds2 = Mathf.FloorToInt(howlonghere - minutes * 60);
    string niceTime2 = string.Format("{0:0}:{1:00}", minutes, seconds);

    if (timeremaining > 0)
    {
        Merchanthuman.enabled = false;
        Merchanthuman.interactable = false;
        Tiimer.text = "Merchant will be here: " + niceTime;
    }
    else
    {
        Tiimer.text = "Merchant is here for: " + niceTime2;
        Merchanthuman.enabled = true;
        Merchanthuman.interactable = true;
    }
}

那“商人在这里是为了：”应该开始新的倒数，这将是第二次。 就像将在这里是5分钟，在这里是2分钟。

Answer 1

让我们将其拆分一下：

public const float TravelTime = 5.0f;
public const float VisitTime = 4.0f;
public float timeremaining;
public float howlonghere;

//Setup initial timers
void Start()
{
    timeremaining = TravelTime;
    howlonghere = VisitTime;
}

//Check each frame for the scenario
void Update()
{
    if (timeremaining > 0)
    {
        string niceTime = ElapseTravel();
        Merchanthuman.enabled = false;
        Merchanthuman.interactable = false;
        Tiimer.text = "Merchant will be here: " + niceTime;
    }
    else
    {
        string niceTime2 = ElapseVisit();
        Tiimer.text = "Merchant is here for: " + niceTime2;
        Merchanthuman.enabled = true;
        Merchanthuman.interactable = true;
    }
}

//Elapse remaining time when merchant travels
private string ElapseTravel()
{
    timeremaining -= Time.deltaTime;
    int minutes = Mathf.FloorToInt(timeremaining / 60F);
    int seconds = Mathf.FloorToInt(timeremaining - minutes * 60);
    return string.Format("{0:0}:{1:00}", minutes, seconds); 
}

//Elapse stay time when merchant is here
private string ElapseVisit()
{
    howlonghere -= Time.deltaTime;
    int minutes2 = Mathf.FloorToInt(howlonghere / 60F);
    int seconds2 = Mathf.FloorToInt(howlonghere - minutes2 * 60);
    if (howlonghere <= 0)
    {
        timeremaining = TravelTime;
        howlonghere = VisitTime;
    }
    return string.Format("{0:0}:{1:00}", minutes2, seconds2);
}

无论情况如何，您都在减少timeremaining和howlonghere 。 您需要拆分两种情况，并根据商人要去的地点或他是否已经在这里的事实，只经过（减少）一个值。

Answer 2

Unity Timer不是负数。 是您自己的变量变为负数。

实际上，您正在检查5分钟并执行timeremaining -= Time.deltaTime; 这将不断减少您的timeremaining变量。

第二件事是您在减少howlonghere的同时减少了多长时间。 因为这里howlonghere的时间少于timeremaining 。

因此，当您的第一个计时器timeremaining <= 0您的第二个计时器howlonghere将变为howlonghere = -3 minutes 。 （假设timeremaining = 5而最初的howlonghere = 2 ）。

如果您不想在这里更改逻辑，该怎么办。

void Update()
{
    timeremaining -= Time.deltaTime;
    int minutes = Mathf.FloorToInt(timeremaining / 60F);
    int seconds = Mathf.FloorToInt(timeremaining - minutes * 60);
    string niceTime = string.Format("{0:0}:{1:00}", minutes, seconds);

    if (timeremaining > 0)
    {
        Merchanthuman.enabled = false;
        Merchanthuman.interactable = false;
        Tiimer.text = "Merchant will be here: " + niceTime;
    }
    else {
        howlonghere -= Time.deltaTime;
        int minutes2 = Mathf.FloorToInt(howlonghere / 60F);
        int seconds2 = Mathf.FloorToInt(howlonghere - minutes * 60);
        string niceTime2 = string.Format("{0:0}:{1:00}", minutes, seconds);   

        Tiimer.text = "Merchant is here for: " + niceTime2;
        Merchanthuman.enabled = true;
        Merchanthuman.interactable = true; 
    }

}

显然，您将对其进行相应的自定义。 但这只是为了让您清楚。