嵌套AWK数组的替代方案？

Question

文件1是

foo"blahblah#AAA17"blahblah
foo"blahblah#BBB64"blahblah
foo"blahblah#CCC53"blahblah
foo"blahblah#DDD59"blahblah
foo"blahblah#EEE22"blahblah
foo"blahblah#FFF49"blahblah

file2是制表符分隔的，并且是

AAA17   something9197
BBB64   something333
CCC53   something268
DDD59   something5050
EEE22   something4643
FFF49   something2

我想向file1中的每一行添加一些文本。 文本将包含file2中的字段2，如下所示。 使用gawk，我可以使用嵌套数组获得所需的结果：

awk -F"\t" 'FNR==NR {arr1[$1]=$2; next} {split($0,arr2,"#|\"")} {print $0": moomoo "arr1[arr2[3]]}' file2 file1
foo"blahblah#AAA17"blahblah: moomoo something9197
foo"blahblah#BBB64"blahblah: moomoo something333
foo"blahblah#CCC53"blahblah: moomoo something268
foo"blahblah#DDD59"blahblah: moomoo something5050
foo"blahblah#EEE22"blahblah: moomoo something4643
foo"blahblah#FFF49"blahblah: moomoo something2

有没有一种不涉及嵌套数组的简单方法？

请注意，这两个文件的行可能会乱码-此处显示的顺序不正确。

Answer 1

所有你需要的是：

$ awk 'NR==FNR{arr[$1]=$2;next} {print $0 ": moomoo", arr[$3]}' file2 FS='[#"]' file1
foo"blahblah#AAA17"blahblah: moomoo something9197
foo"blahblah#BBB64"blahblah: moomoo something333
foo"blahblah#CCC53"blahblah: moomoo something268
foo"blahblah#DDD59"blahblah: moomoo something5050
foo"blahblah#EEE22"blahblah: moomoo something4643
foo"blahblah#FFF49"blahblah: moomoo something2

Answer 2

假设文件不是太大，您的解决方案看起来已经不错。 “嵌套数组”不会像“嵌套循环”那样在时间上浪费时间。 但是还有另一种使用内置join ，尽管我不知道是否称其为“简单”：

cat file1|awk -F"#|\"" '{print $3,$0": moomoo"}'|sort >file3
sort file2|join file3 -|cut -d " " -f 2-