为什么`input`不显示在python上？

Question

我正在做一个简单的游戏，有2个玩家和20个棍棒。 每个玩家可以选择1-3个杆，而玩家选择最后一个杆将输掉比赛。

def stix(num):
    for _ in range(5): print('|  '* num)
    print
stix(20)
game_over = 0
while game_over !=0:
    players={}
    for i in range(2):
        players[i] = int(input('Player %d: Please pick stick(s) up to 3' %i))
        if players > 3 or players<0:
            print('Please pick between 1 - 3 stick(s)')
        else:
            stix-=players
            if stix <= 0:
                print('Player[i] lost')
                break
            else:
                print('There is %d stick(s) left' %stix)
                print(stix-players[i])

因此，功能stix显示20条，仅此而已。 它不要求please pick stick(s) up to 3 。 我在这里想念什么？

*我正在使用python 2.6

提前致谢！

Answer 1

您根本不会进入while循环：

game_over = 0
while game_over !=0: # Evaluated to false the first time so it's skipped.
    # code

因此，在这种情况下，错误与input()无关

Answer 2

您的while情况是“ game_over”不等于0，而是直接位于其上方的行将其设置为0。

我认为您想要的是：

game_over = True
while not game_over:
   ...

Answer 3

您的问题是当game_over 不为 0时，您的while循环将运行，但是在前面的一行中，您将game_over设置为0。

game_over = 0
while game_over !=0:
    ...

因此，将game_over更改为1，您的代码将起作用！

def stix(num):
    for _ in range(5): print('|  '* num)
    print
stix(20)
game_over = 1
while game_over !=0:
    players={}
    for i in range(2):
        players[i] = int(input('Player %d: Please pick stick(s) up to 3' %i))
        if players > 3 or players<0:
            print('Please pick between 1 - 3 stick(s)')
        else:
            stix-=players
            if stix <= 0:
                print('Player[i] lost')
                break
            else:
                print('There is %d stick(s) left' %stix)
                print(stix-players[i])