I am making simple game which there are 2 players and 20 sticks given. Each player can pick 1-3 stick(s) and player picks last stick will lose the game.
def stix(num):
for _ in range(5): print('| '* num)
print
stix(20)
game_over = 0
while game_over !=0:
players={}
for i in range(2):
players[i] = int(input('Player %d: Please pick stick(s) up to 3' %i))
if players > 3 or players<0:
print('Please pick between 1 - 3 stick(s)')
else:
stix-=players
if stix <= 0:
print('Player[i] lost')
break
else:
print('There is %d stick(s) left' %stix)
print(stix-players[i])
So, function stix
shows 20 sticks and that's it. It does not ask please pick stick(s) up to 3
. What did I miss in here?
*I am using python 2.6
Thanks in advance!
You're never entering the while loop at all:
game_over = 0
while game_over !=0: # Evaluated to false the first time so it's skipped.
# code
So the error, in this case, has nothing to do with input()
Your while case is that "game_over" does not equal 0 but the line directly above it sets it to 0.
I think what you want is:
game_over = True
while not game_over:
...
Your problem is that your while
loop is going to run while game_over is not 0, but in the line before, you set game_over
to 0.
game_over = 0
while game_over !=0:
...
Thus, change game_over
to 1, and your code will work!
def stix(num):
for _ in range(5): print('| '* num)
print
stix(20)
game_over = 1
while game_over !=0:
players={}
for i in range(2):
players[i] = int(input('Player %d: Please pick stick(s) up to 3' %i))
if players > 3 or players<0:
print('Please pick between 1 - 3 stick(s)')
else:
stix-=players
if stix <= 0:
print('Player[i] lost')
break
else:
print('There is %d stick(s) left' %stix)
print(stix-players[i])
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