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如果联系人有超过1个电话号码,则显示详细的联系人卡片

[英]Display detailed contact card if contact has more than 1 phone number

如果联系人只有一个电话号码,我想选择它。 如果它有超过1个电话号码,那么我想显示详细的联系卡。

我使用下面的方法,工作正常。

- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person {

    if (person != nil) {
        ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
        if (ABMultiValueGetCount(phoneNumbers) == 1) {
            //Do stuff to select phone number
        }
    }
}

然后,我实现此实用程序方法以显示详细联系卡:

- (void)peoplePickerNavigationController:(ABPeoplePickerNavigationController *)peoplePicker didSelectPerson:(ABRecordRef)person property:(ABPropertyID)property identifier:(ABMultiValueIdentifier)identifier {

    NSString* phone = nil;
    ABMultiValueRef phoneNumbers = ABRecordCopyValue(person, kABPersonPhoneProperty);
    if (ABMultiValueGetCount(phoneNumbers) > 0) {
        CFIndex index = ABMultiValueGetIndexForIdentifier(phoneNumbers, identifier);
        phone = (__bridge_transfer NSString*)ABMultiValueCopyValueAtIndex(phoneNumbers, index);
    }
}

但这种方法永远不会被调用? 如果我注释掉第一个方法,那么第二个方法就会被调用。 我怎么能同时打电话,还是有其他办法实现这一目标?

解决方法是在启动peoplePicker之前添加一个predicate ,在这种情况下它将是:

-(void)getContacts {
    ABPeoplePickerNavigationController *peoplePicker = [[ABPeoplePickerNavigationController alloc] init];
    peoplePicker.peoplePickerDelegate = self;
    if ([peoplePicker respondsToSelector:@selector(setPredicateForSelectionOfPerson:)])
    {
        // The people picker will select a person that has exactly one phone number and call peoplePickerNavigationController:didSelectPerson:,
        // otherwise the people picker will present an ABPersonViewController for the user to pick one of the Phone Numbers.
        peoplePicker.predicateForSelectionOfPerson = [NSPredicate predicateWithFormat:@"phoneNumbers.@count = 1"];

    }
    [self presentViewController:peoplePicker animated:NO completion:nil];
}

同样在emailAdresses的情况下,用@"emailAddresses.@count = 1"替换: @"phoneNumbers.@count = 1" @"emailAddresses.@count = 1"

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