[英]Python Tkinter loop through 3 labels updating with each new list value
[英]Python 2.7 Tkinter: loop through labels to display data on new row
我目前正在尝试创建一个天气应用程序,并且我的代码可以打印出接下来7天的天气,天气预报和最高气温。
weather_req_url = "https://api.forecast.io/forecast/%s/%s,%s?units=uk2" % (weather_api_token, lat,lon)
r = requests.get(weather_req_url)
weather_obj = json.loads(r.text)
t = datetime.now()
for i, x in enumerate(weather_obj["daily"]["data"][1:8]):
print (t+timedelta(days=i+1)).strftime("\t%a"), x['icon'], ("%.0f" % x['temperatureMax'])
此代码将这些信息打印在外壳程序中:
Sat rain 20
Sun partly-cloudy-day 21
Mon clear-day 26
Tue partly-cloudy-night 29
Wed rain 28
Thu rain 24
Fri rain 23
我目前有一个框架和一个标签,但是我不想为每一行手动创建一个标签。
self.degreeFrm = Frame(self, bg="black")
self.degreeFrm.grid(row = 0, column = 0)
self.temperatureLbl = Label(self.degreeFrm, font=('Helvetica Neue UltraLight', 80), fg="white", bg="black")
self.temperatureLbl.grid(row = 0, column = 0, sticky = E)
有没有一种方法可以运行用于创建和显示带有for循环的每次迭代信息的标签的第一块代码。
就像上面的评论一样,遵循以下原则可以解决问题:
forecasts = []
for i, x in enumerate(weather_obj["daily"]["data"][1:8]):
forecasts.append((t+timedelta(days=i+1)).strftime("\t%a"), x['icon'], ("%.0f" % x['temperatureMax']))
row_num = 0
for forecast in forecasts:
l = Label(self.degreeFrm, font=('Helvetica Neue UltraLight', 80), text = forecast)
l.grid(row = row_num, column = 0, sticky= E)
row_num +=1
希望这可以帮助。
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