[英]List index while loop python
我有以下代码的问题。 当我输入确切的密码字符时,以下代码与密码不匹配。
#initiate words for guessing secretWords =['cat','mouse','donkey','ant','lion']
#Generate a random word to be guessed generateWord = (random.choice(secretWords))
# User have attempts only to the random generate words LeftCount = 6
generateWord = ["_"] * len(secretWords) userInput="" LetterNumber=0 RightGuess =0
while (LeftCount !=0):
print ("Word Contains", len(generateWord),"letters")
print ("You have", str(LeftCount),"attempts remaining")
print ("\n")
print(generateWord)
print ("\n")
userInput=input("Enter word: ")
while(LetterNumber< len(generateWord)):
if(generateWord[LetterNumber] == userInput):
generateWord[LetterNumber]= userInput
RightGuess +=1
LetterNumber +=1
LeftCount -=1
LetterNumber=0
if (RightGuess == len(generateWord)):
print ("Congratulations")
break
if(LeftCount ==0):
print ("Game over")
为什么要将 generateWord 中的一个字母与整个 userInput 进行比较?
if(generateWord[LetterNumber] == userInput):
该行将“LetterNumber”索引处的字符与 userInput 进行比较,因此如果用户输入一个单词,它将永远不会返回 true。
如果您试图计算用户猜测中正确字母的数量,您不应该将用户输入中的每个字母与“generateWord”中的相应字母进行比较。
if(generateWord[LetterNumber] == userInput[LetterNumber]):
还有一些一般性的观点,变量名不应该以大写开头,根据 Python 标准应该是“letter_number”。 尝试改进您的变量名称,也许称之为“generated_word”,而不是“generate_word”。 “Generate_word”暗示它是一个函数,因为 generate 是一个动词。
if 语句之后的那一行也将整个 userInput 重新分配到 generateWord 值中,在字母索引处,你为什么要这样做?
最后,您需要在 while 循环的结尾或开头生成一个新单词,因为此时您只在开头生成一个单词,然后它将在每次迭代中使用相同的单词。
尝试使用 print 打印出您的一些变量,它会帮助您调试程序,因为它绝对不是您期望的那样。
您正在覆盖您选择的单词。 generateWord
同时是秘密词,也是用户输入。 这是行不通的。 这是应该做你想做的事情(我还纠正了一些其他问题):
import random
secretWords = ["cat", "mouse", "donkey", "ant", "lion"]
generatedWord = random.choice(secretWords)
leftCount = 6
userWord = ["_"] * len(generatedWord)
refusedLetters = ""
#returns all positions of character ch in the string s
def findOccurences(s, ch):
return [i for i, letter in enumerate(s) if letter == ch]
print("Word contains", len(generatedWord), "letters")
while(leftCount > 0 and generatedWord != "".join(userWord)):
print ("\n")
print ("You have", str(leftCount), "attempts remaining")
print ("Letters not present in your word:", "".join(sorted(refusedLetters)))
print ("Your word so far: ","".join(userWord))
print ("\n")
#checks that the user enters something
userInput = ""
while not len(userInput):
userInput=input("Enter letter or word: ")
userInput = userInput.lower()
#if len > 1, then the user has tried to guess the whole word:
if len(userInput) > 1:
if generatedWord == userInput:
print("Congratulations")
break
else:
print("Wrong word, sorry")
#len == 1, thus the user asked for one letter
else:
#if letter isn't already found
if not userInput in userWord:
#for all occurences of the letter in the secret word
occurences = findOccurences(generatedWord, userInput)
for occurence in occurences:
userWord[occurence] = userInput
#if the letter was not found
if not occurences:
#if the letter has already been proposed
if userInput in refusedLetters:
print("You have already tried this letter")
continue
else:
refusedLetters += userInput
else:
print("You have already tried this letter")
continue
leftCount -= 1
#the else statement will only be entered if we did not exit the previous loop via a break.
#Thus, if the word has already been found, nothing happens here.
else:
if generatedWord == "".join(userWord):
print("Congratulations")
else:
print("Game over")
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