C++ 函数未声明？

Question

我正在尝试制作一个命令行游戏，并声明了这两个函数，但是当我调用playerAttack(); 构建消息说error: playerAttack start was not declared in this scope声明我在int main() {...}函数之前声明了函数playerAttack()和cpuAttack()如果有帮助的话。 请帮助提前谢谢。

void cpuAttack() {
    if (playerHealth > 0 && cpuHealth > 0) {
        cout << "Attack Direction (left, right, or center): ";
        cin >> attack;
        cout << name << " attacks from the " << attack << endl;
        srand(time(0));
        cpuBlock = attDir[rand() % 2];
        cout << "CPU-1 blocks the " << cpuBlock << endl;
        if (attack != cpuBlock) {
            cpuHealth - dmg;
        } else {cpuHealth = cpuHealth - (dmg + 20);}
        playerAttack();
    } else if (playerHealth > 0 && cpuHealth <= 0) {
        cout << "\n" << name << " has won the game.\n";
    } else if (playerHealth <= 0 && cpuHealth > 0) {
        cout << "\nCPU-1 has won the game.\n";
    }
}

和

void playerAttack() {
    if (playerHealth > 0 && cpuHealth > 0) {
        cout << "Attack Direction (left, right, or center): ";
        cin >> attack;
        cout << name << " attacks from the " << attack << endl;
        srand(time(0));
        cpuBlock = attDir[rand() % 2];
        cout << "CPU-1 blocks the " << cpuBlock << endl;
        if (attack != cpuBlock) {
            cpuHealth - dmg;
        } else {cpuHealth = cpuHealth - (dmg + 20);}
        cpuAttack();
    } else if (playerHealth > 0 && cpuHealth <= 0) {
        cout << "\n" << name << " has won the game.\n";
    } else if (playerHealth <= 0 && cpuHealth > 0) {
        cout << "\nCPU-1 has won the game.\n";
    }
}

Answer 1

由于这两个函数相互依赖，因此在定义一个函数之前，其中一个函数必须已经知道另一个函数。 解决方案是在定义之前声明它们：

void cpuAttack();
void playerAttack();

// now define them ...

或者，您可以通过允许其他东西控制轮流来摆脱相互依赖，从而不将调用堆叠在一起（在某些情况下可能会导致堆栈溢出）。