以PHP变量为参数的JavaScript函数

Question

我搜索了有关在JS函数中转义参数的信息，并且尝试了很多建议，但均无济于事。 这是代码：

echo '<a class="btn btn-xs btn-danger" onclick="delete('.$fetch['bicc'].')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

我总是收到此错误：

SyntaxError: identifier starts immediately after numeric literal
delete(123456789_7_ZY7)

Answer 1

您需要添加引号，您的param是字符串类型：

echo '<a class="btn btn-xs btn-danger" onclick="delete(\''.$fetch['bicc'].'\')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 2

您忘记了\\"

onClick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>

所以应该像这样：

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 3

根据经验，如果要在JavaScript代码中使用PHP变量，则需要将它们包装在json_encode ：

echo '<a class="btn btn-xs btn-danger" onclick="delete('.json_encode($fetch['bicc']).')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

json_encode能够接受大多数PHP变量（字符串，数组，关联数组），并将其正确编码为与JavaScript对应的变量（例如，为字符串添加引号）。

Answer 4

您应该添加引号，因为参数是字符串

echo "<a class=\"btn btn-xs btn-danger\" onclick=\"delete(\"${fetch['bicc']}\")\"><span class=\"glyphicon glyphicon-remove\"></span> Remove</a>";

Answer 5

$ fetch ['bicc']是否具有字符串类型值？

如是：

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 6

$data = str_replace('_', ' ', $fetch['bicc']);
echo '<a class="btn btn-xs btn-danger" onclick="delete('.$data.')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'