以PHP变量为参数的JavaScript函数

Question

I've searched about escaping the parameter inside the JS function and I've tried lots of suggestions but none works. Here is the code:

echo '<a class="btn btn-xs btn-danger" onclick="delete('.$fetch['bicc'].')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

I always get this error:

SyntaxError: identifier starts immediately after numeric literal
delete(123456789_7_ZY7)

Answer 1

您需要添加引号，您的param是字符串类型：

echo '<a class="btn btn-xs btn-danger" onclick="delete(\''.$fetch['bicc'].'\')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 2

You forgot about \\"

onClick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>

So it should be like:

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 3

As a rule of thumb, if you want to use PHP variables in your JavaScript code, you need to wrap them in json_encode :

echo '<a class="btn btn-xs btn-danger" onclick="delete('.json_encode($fetch['bicc']).')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

json_encode is able to take most PHP variables (strings, arrays, associative arrays) and correctly encode them as their JavaScript counterparts (eg, adding quotes for strings).

Answer 4

您应该添加引号，因为参数是字符串

echo "<a class=\"btn btn-xs btn-danger\" onclick=\"delete(\"${fetch['bicc']}\")\"><span class=\"glyphicon glyphicon-remove\"></span> Remove</a>";

Answer 5

$fetch['bicc'] has string type value?

if yes:

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 6

$data = str_replace('_', ' ', $fetch['bicc']);
echo '<a class="btn btn-xs btn-danger" onclick="delete('.$data.')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'