JavaScript function with PHP variable as parameter

Question

I've searched about escaping the parameter inside the JS function and I've tried lots of suggestions but none works. Here is the code:

echo '<a class="btn btn-xs btn-danger" onclick="delete('.$fetch['bicc'].')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

I always get this error:

SyntaxError: identifier starts immediately after numeric literal
delete(123456789_7_ZY7)

Answer 1

您需要添加引号，您的param是字符串类型：

echo '<a class="btn btn-xs btn-danger" onclick="delete(\''.$fetch['bicc'].'\')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 2

You forgot about \\"

onClick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>

So it should be like:

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 3

As a rule of thumb, if you want to use PHP variables in your JavaScript code, you need to wrap them in json_encode :

echo '<a class="btn btn-xs btn-danger" onclick="delete('.json_encode($fetch['bicc']).')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

json_encode is able to take most PHP variables (strings, arrays, associative arrays) and correctly encode them as their JavaScript counterparts (eg, adding quotes for strings).

Answer 4

您应该添加引号，因为参数是字符串

echo "<a class=\"btn btn-xs btn-danger\" onclick=\"delete(\"${fetch['bicc']}\")\"><span class=\"glyphicon glyphicon-remove\"></span> Remove</a>";

Answer 5

$fetch['bicc'] has string type value?

if yes:

echo '<a class="btn btn-xs btn-danger" onclick="delete(\"'.$fetch['bicc'].'\")"><span class="glyphicon glyphicon-remove"></span> Remove</a>'

Answer 6

$data = str_replace('_', ' ', $fetch['bicc']);
echo '<a class="btn btn-xs btn-danger" onclick="delete('.$data.')"><span class="glyphicon glyphicon-remove"></span> Remove</a>'