即使宽度相等，为什么我的标签尺寸不同？

Question

我有一个位于row = 0的框架，其中包含我想在column = 2 ＆ column = 3中使用的文本High和Low 。 我在其下面的另一行包含一个数值。 但是在标签上，我将宽度设置为全部等于7。

我在这里做错了什么？

##Forecast Frame
self.ForecastFrame = Frame(self, bg='black')
self.ForecastFrame.grid(row = 0, column = 0)

##Forecast Title
self.forecastTitle = Frame(self.ForecastFrame, bg='white')
self.forecastTitle.grid(row = 0, column = 0, sticky = E)      

self.forecastTitleHighLabel = Label(self.forecastTitle, text='High', font=('HelveticaNeue Light', 12), fg='white', bg='green', width = '7', anchor='center')
self.forecastTitleHighLabel.grid(row = 0, column = 2, sticky = E)

self.forecastTitleLowLabel = Label(self.forecastTitle, text='Low', font=('HelveticaNeue Light', 12), fg='white', bg='blue', width = '7', anchor='center')
self.forecastTitleLowLabel.grid(row = 0, column = 3, sticky = E)

##Forecast One Labels
self.forecastOneDate = ''
self.forecastOneIcon = ''
self.forecastOneHigh = ''
self.forecastOneLow = ''

self.forecastOne = Frame(self.ForecastFrame, bg='black')
self.forecastOne.grid(row = 1, column = 0)

self.forecastOneDateLabel = Label(self.forecastOne, font=('HelveticaNeue Light', 12), fg='white', bg='yellow', width=10, anchor='w')
self.forecastOneDateLabel.grid(row = 0, column = 0, sticky = W)

self.forecastOneIconLabel = Label(self.forecastOne, bg='red', width=50)
self.forecastOneIconLabel.grid(row = 0, column = 1, sticky = W)

self.forecastOneHighLabel = Label(self.forecastOne, font=('HelveticaNeue Light', 12, 'bold'), fg='white', bg='blue', width = '7', anchor='center')
self.forecastOneHighLabel.grid(row = 0, column = 2, sticky = E)

self.forecastOneLowLabel = Label(self.forecastOne, font=('HelveticaNeue Light', 12, 'bold'), fg='white', bg='green', width = '7', anchor='center')
self.forecastOneLowLabel.grid(row = 0, column = 3, sticky = E)

Answer 1

effbot.org： 标签

宽度=

标签的宽度。 如果标签显示文本，则大小以文本单位给出。 如果标签显示图像，则以像素 （或屏幕单位 ）为单位指定尺寸。 如果将大小设置为0或省略，则根据标签内容进行计算。 （宽度/宽度）

这意味着width取决于字体大小和粗细。

import tkinter as tk

root = tk.Tk()


l1 = tk.Label(root, text='Hello', width=7, fg='white', bg='blue')

f = ('HelveticaNeue Light', 12)

l2 = tk.Label(root, text='Hello', width=7, fg='white', bg='green', font=f)

f = ('HelveticaNeue Light', 12, 'bold')

l3 = tk.Label(root, text='Hello', width=7, fg='white', bg='red', font=f)


l1.grid()
l2.grid()
l3.grid()

root.mainloop()