[英]Swift : How to sort alphabetically but with letters first
我有一个Realm结果列表:
subsList = RealmDB.objects(Downloads).filter("isActive = true").sorted("name", ascending: true)
它显示有序的结果,但第一个结果是“(项目1)”或1个项目,然后是A项目,B项目等。
如何以A项,B项等为首,最后显示(项1),1项的方式对它进行排序?
注意:对于不了解领域的人,可以使用NSPredicate进行排序
多谢你们
编辑:根据评论,我得到
-chloro
(+-)-1,2,3-octa
(amino)
1-propanol
acetone
benzin
dinoterb
TNT
我需要
acetone
benzin
dinoterb
TNT
-chloro
(+-)-1,2,3-octa
(amino)
1-propanol
这只是一个示例,请修复代码以使其看起来更好。
var arr = ["-chloro", "(+-)-1,2,3-octa", "(amino)", "1-propanol", "acetone", "benzin","dinoterb","TNT"]
func matches(for regex: String, in text: String) -> [String] {
do {
let regex = try NSRegularExpression(pattern: regex)
let nsString = text as NSString
let results = regex.matches(in: text, range: NSRange(location: 0, length: nsString.length))
return results.map { nsString.substring(with: $0.range)}
} catch let error {
print("invalid regex: \(error.localizedDescription)")
return []
}
}
arr.sort { (s1, s2) -> Bool in
let matched = matches(for: "[0-9,\\(,\\-]", in: s1)
let matched2 = matches(for: "[0-9\\(,\\-]", in: s2)
if matched.isEmpty && matched2.isEmpty {
return s1.lowercased() < s2.lowercased()
} else if matched.isEmpty && !matched2.isEmpty {
return true
} else if !matched.isEmpty && matched2.isEmpty {
return false
} else {
return matched.first! < matched2.first!
}
}
结果-> [“丙酮”,“苯并”,“ dinoterb”,“ TNT”,“(+-)-1,2,3-辛基”,“(氨基)”,“-氯”,“ 1-丙醇” “]
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