[英]displaying information on another frame? (tkinter python)
所以有这个stackoverflow问题:
这看起来像是构建应用程序的美好基础。 但是,如果我要在startPage上设置多个按钮,并在PageOne上显示适当的数据怎么办? 这是我的尝试:
import tkinter as tk
from functools import partial
characters = {"character1": "abc", "character2": "def", "character3": "ghi", "character4": "jkl", "character5": "mnp", "character6": "qrs" }
class AdventureGame:
''' controller for managiging frames '''
def __init__(self, master):
self.master = master
self.frames = {}
for F in (StartGame,ShowCharacters,CharacterDetail):
frame = F(parent=master, controller=self)
self.frames[F.__name__] = frame
frame.grid(row=0, column=0, sticky="nsew")
''' rais the first frame '''
self.raise_frame("StartGame")
def raise_frame(self,page_name):
''' raise a frame '''
frame = self.frames[page_name]
frame.tkraise()
def lower_frame(self,page_name):
''' lower a frame '''
frame = self.frames[page_name]
frame.lower()
class StartGame(tk.Frame):
''' introduction screen of the game '''
def __init__(self, parent, controller):
super(StartGame,self).__init__(parent)
self.controller = controller
''' introduction text '''
tk.Label(self, text="welcome to this game").grid()
tk.Button(self, text="next", command=lambda: controller.raise_frame("ShowCharacters")).grid()
class ShowCharacters(tk.Frame):
''' main frame, overview of all pokemon '''
def __init__(self, parent, controller):
super(ShowCharacters,self).__init__(parent)
self.controller = controller
for row, character in enumerate(characters):
name_label = tk.Label(self, text=characters[character])
name_label.grid(row=row,column=0)
info_button = tk.Button(self, text="view info", command=partial(self.switch,character))
info_button.grid(row=row,column=1)
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
class CharacterDetail(tk.Frame):
''' detail view of pokemon '''
def __init__(self, parent, controller):
super(CharacterDetail,self).__init__(parent)
self.controller = controller
tk.Button(self, text="back", command=lambda: controller.lower_frame("CharacterDetail")).grid()
# somehow display characters name here
def showdetail(self):
tk.Label(self, text="test").grid()
def main():
root = tk.Tk()
app = AdventureGame(root)
root.mainloop()
main()
感觉就像钥匙在控制器中一样,如下所述:
感觉就像我在想什么,有人有主意吗? 还是我一起思考方向错误?
如果我尝试显示细节:
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
CharacterDetail.showdetail(self)
它显示在ShowCharacters框架而不是CharacterDetail框架
我猜是因为self
是框架,这是ShowCharacters的self
我需要对控制器做一些事情,但是我的脑袋一片空白
所以现在我将信息传递给控制器:
import tkinter as tk
from functools import partial
characters = {"character1": "abc", "character2": "def", "character3": "ghi", "character4": "jkl", "character5": "mnp", "character6": "qrs" }
class AdventureGame:
''' controller for managiging frames '''
def __init__(self, master):
self.master = master
self.frames = {}
for F in (StartGame,ShowCharacters,CharacterDetail):
frame = F(parent=master, controller=self)
self.frames[F.__name__] = frame
frame.grid(row=0, column=0, sticky="nsew")
self.app_data = {"test": "test"}
''' rais the first frame '''
self.raise_frame("StartGame")
def raise_frame(self,page_name):
''' raise a frame '''
frame = self.frames[page_name]
frame.tkraise()
def lower_frame(self,page_name):
''' lower a frame '''
frame = self.frames[page_name]
frame.lower()
class StartGame(tk.Frame):
''' introduction screen of the game '''
def __init__(self, parent, controller):
super(StartGame,self).__init__(parent)
self.controller = controller
''' introduction text '''
tk.Label(self, text="welcome to this game").grid()
tk.Button(self, text="next", command=lambda: controller.raise_frame("ShowCharacters")).grid()
class ShowCharacters(tk.Frame):
''' main frame, overview of all pokemon '''
def __init__(self, parent, controller):
super(ShowCharacters,self).__init__(parent)
self.controller = controller
for row, character in enumerate(characters):
name_label = tk.Label(self, text=characters[character])
name_label.grid(row=row,column=0)
info_button = tk.Button(self, text="view info", command=partial(self.switch,character))
info_button.grid(row=row,column=1)
def switch(self, character):
test = self.controller.raise_frame("CharacterDetail")
CharacterDetail.example(self)
class CharacterDetail(tk.Frame):
''' detail view of pokemon '''
def __init__(self, parent, controller):
super(CharacterDetail,self).__init__(parent)
self.controller = controller
tk.Button(self, text="back", command=lambda: controller.lower_frame("CharacterDetail")).grid()
def example(self):
tk.Label(self, text=self.controller.app_data["test"]).grid()
def main():
root = tk.Tk()
app = AdventureGame(root)
root.mainloop()
main()
标签仍然在错误的框架上,我如何获得正确的自我,以便可以将标签添加到正确的框架?
当您在ShowCharacters
类的函数switch(...)
中调用CharacterDetail.example(self)
时, self
将是ShowCharacters
类。 因此,在类CharacterDetail
函数example(self)
中创建的标签将位于ShowCharacters
框架中。
尝试:
返回AdventureGame
类的raise_frame(...)
函数中的凸起框架:
def raise_frame(self, page_name): frame = self.frames[page_name] frame.tkraise() return frame # return the raised frame
修改ShowCharacters
类的功能switch(...)
:
def switch(self, character): frame = self.controller.raise_frame("CharacterDetail") frame.example()
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