[英]C# string parse
我有这样的字符串
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'"
每对单引号都是一个以逗号分隔的字段。 我想清空字符串中的第8个字段。 我不能简单地执行replace("MUL,NBLD,NITA,NUND","")
因为该字段可以包含任何内容。 还请注意,第4个字段是数字,因此在5
周围没有单引号。
我该如何实现?
static void Main()
{
var temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'";
var parts = Split(temp).ToArray();
parts[7] = null;
var ret = string.Join(",", parts);
// or replace the above 3 lines with this...
//var ret = string.Join(",", Split(temp).Select((v,i)=>i!=7 ? v : null));
//ret == "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40',,'','Address line 2'"
}
public static IEnumerable<string> Split(string input, char delimiter = ',', char quote = '\'')
{
string temp = "";
bool skipDelimiter = false;
foreach (var c in input)
{
if (c == quote)
skipDelimiter = !skipDelimiter;
else if (c == delimiter && !skipDelimiter)
{
//do split
yield return temp;
temp = "";
continue;
}
temp += c;
}
yield return temp;
}
我在下面做了一个小实现。 我在评论中解释了逻辑。 基本上,您想编写一个简单的解析器来完成您描述的内容。
edit0:刚意识到我做的与您要求的相反。.现在修复
edit1:将字符串替换为null,而不是从逗号分隔的列表中删除整个字段。
static void Main(string[] args)
{
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'";
//keep track of the single quotes
int singleQuoteCount= 0;
//keep track of commas
int comma_count = 0;
String field = "";
foreach (Char chr in temp)
{
//add to the field string if we are not between the 7th and 8th comma not counting commas between single quotes
if (comma_count != 7)
field += chr;
//plug in null string between two single quotes instead of whatever chars are in the eigth field.
else if (chr == '\'' && singleQuoteCount %2 ==1)
field += "\'',";
if (chr == '\'') singleQuoteCount++;
//only want to add to comma_count if we are outside of single quotes.
if (singleQuoteCount % 2 == 0 && chr == ',') comma_count++;
}
}
如果在字段内(例如:“ MUL-NBLD-NITA-NUND”)使用“-”(或其他字符)代替“,”,则可以使用以下代码:
static void Main(string[] args)
{
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL-NBLD-NITA-NUND','','Address line 2'";
temp = replaceField(temp, 8);
}
static string replaceField(string list, int field)
{
string[] fields = list.Split(',');
string chosenField = fields[field - 1 /*<--Arrays start at 0!*/];
if(!(field == fields.Length))
list = list.Replace(chosenField + ",", "");
else
list = list.Replace("," + chosenField, "");
return list;
}
//Return-Value: "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','','Address line 2'"
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