[英]C# string parse
我有這樣的字符串
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'"
每對單引號都是一個以逗號分隔的字段。 我想清空字符串中的第8個字段。 我不能簡單地執行replace("MUL,NBLD,NITA,NUND","")
因為該字段可以包含任何內容。 還請注意,第4個字段是數字,因此在5
周圍沒有單引號。
我該如何實現?
static void Main()
{
var temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'";
var parts = Split(temp).ToArray();
parts[7] = null;
var ret = string.Join(",", parts);
// or replace the above 3 lines with this...
//var ret = string.Join(",", Split(temp).Select((v,i)=>i!=7 ? v : null));
//ret == "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40',,'','Address line 2'"
}
public static IEnumerable<string> Split(string input, char delimiter = ',', char quote = '\'')
{
string temp = "";
bool skipDelimiter = false;
foreach (var c in input)
{
if (c == quote)
skipDelimiter = !skipDelimiter;
else if (c == delimiter && !skipDelimiter)
{
//do split
yield return temp;
temp = "";
continue;
}
temp += c;
}
yield return temp;
}
我在下面做了一個小實現。 我在評論中解釋了邏輯。 基本上,您想編寫一個簡單的解析器來完成您描述的內容。
edit0:剛意識到我做的與您要求的相反。.現在修復
edit1:將字符串替換為null,而不是從逗號分隔的列表中刪除整個字段。
static void Main(string[] args)
{
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL,NBLD,NITA,NUND','','Address line 2'";
//keep track of the single quotes
int singleQuoteCount= 0;
//keep track of commas
int comma_count = 0;
String field = "";
foreach (Char chr in temp)
{
//add to the field string if we are not between the 7th and 8th comma not counting commas between single quotes
if (comma_count != 7)
field += chr;
//plug in null string between two single quotes instead of whatever chars are in the eigth field.
else if (chr == '\'' && singleQuoteCount %2 ==1)
field += "\'',";
if (chr == '\'') singleQuoteCount++;
//only want to add to comma_count if we are outside of single quotes.
if (singleQuoteCount % 2 == 0 && chr == ',') comma_count++;
}
}
如果在字段內(例如:“ MUL-NBLD-NITA-NUND”)使用“-”(或其他字符)代替“,”,則可以使用以下代碼:
static void Main(string[] args)
{
string temp = "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','MUL-NBLD-NITA-NUND','','Address line 2'";
temp = replaceField(temp, 8);
}
static string replaceField(string list, int field)
{
string[] fields = list.Split(',');
string chosenField = fields[field - 1 /*<--Arrays start at 0!*/];
if(!(field == fields.Length))
list = list.Replace(chosenField + ",", "");
else
list = list.Replace("," + chosenField, "");
return list;
}
//Return-Value: "'ADDR_LINE_2','MODEL','TABLE',5,'S','Y','C40','','Address line 2'"
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