检查python中变量的状态

Question

我正在尝试使用if语句进行审核，尽管播放列表包含单词“ http”，但是playlist should have value 'http: //*********/****.m3u但如果播放列表没有包含单词“ http”，那么我想获得值playlist '"file: ///" + playlist'

def GETPLAYLIST(): 
    playlistset = int(addon.getSetting('playlistset')) + 1 
    playlist = addon.getSetting('playlist' + str(playlistset)) 
    if 'http' in 'playlist'
    else:
        playlistlist = "file:///" + playlist
    return playlist

Answer 1

您可以反转条件并执行以下操作：

def GETPLAYLIST(): 
    playlistset = int(addon.getSetting('playlistset')) + 1 
    playlist = addon.getSetting('playlist' + str(playlistset)) 
    if not 'http' in playlist:
        playlist = "file:///" + playlist
    return playlist