套接字错误后继续循环

Question

我正在使用python循环查找开放端口。 它应该工作的方式是，如果我列表中的端口已打开并接受tcp连接，它将向我发送响应，否则，它将跳至下一个端口号。

我遇到的问题是，如果第一个端口没有响应，我从套接字收到错误，则循环停止。 这是脚本，包括如何定义我的端口列表。

import numpy;
import socket;
import sys;

with open("ports.ls") as f:
    ports = f.read().split(",");

portslist = []
for i in ports:
    portslist.append(i.strip());

portslist = [int(i) for i in portslist]

for i in portslist:
    target_host = sys.argv[1];
    target_port = i;
    print "[*] port:%d" % target_port;
    client = socket.socket(socket.AF_INET, socket.SOCK_STREAM);
    client.connect((target_host, i));
    client.send("GET / HTTP/1.1\r\nHost: %s\r\n\r\n" % target_host);
    response = client.recv(4096);
    print response;

我得到的错误是

socket.error: [Errno 11] Resource temporarily unavailable

尽管第一个端口没有响应，如何继续循环到下一个迭代？

Answer 1

假设这是此脚本中引发的异常，并且未从远程服务器传递回去，则只需添加一个异常处理程序即可。

...并摆脱分号！

import numpy
import socket
import sys

with open("ports.ls") as f:
    ports = f.read().split(",")

portslist = []
for i in ports:
    portslist.append(i.strip())

portslist = [int(i) for i in portslist]

for i in portslist:
    target_host = sys.argv[1]
    target_port = i
    print "[*] port:%d" % target_port
    try:
        client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
        client.connect((target_host, i))
        client.send("GET / HTTP/1.1\r\nHost: %s\r\n\r\n" % target_host)
        response = client.recv(4096)
        print response
    except socket.error as e:
        print e