[英]Extracting a string from data field in sql server
如果您愿意使用表值函数而不使用2016。
厌倦了提取字符串(charindex,left,right,substring等),我修改了Parse / Split函数以接受两个NON-LIKE分隔符。 就您而言, <和>
例
Declare @YourTable table (ID int,QuestionTags varchar(max))
Insert Into @YourTable values
(1,'<php><arrays><cloud><tag-cloud>')
,(2,'<windows><mailto>')
Select A.ID
,B.*
From @YourTable A
Cross Apply [dbo].[udf-Str-Extract](A.QuestionTags,'<','>') B
退货
ID RetSeq RetPos RetVal
1 1 2 php
1 2 7 arrays
1 3 15 cloud
1 4 22 tag-cloud
2 1 2 windows --<< Second Record
2 2 11 mailto
UDF(如果有兴趣)
CREATE FUNCTION [dbo].[udf-Str-Extract] (@String varchar(max),@Delimiter1 varchar(100),@Delimiter2 varchar(100))
Returns Table
As
Return (
with cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (IsNull(DataLength(@String),0)) Row_Number() over (Order By (Select NULL)) From (Select N=1 From cte1 N1,cte1 N2,cte1 N3,cte1 N4,cte1 N5,cte1 N6) A ),
cte3(N) As (Select 1 Union All Select t.N+DataLength(@Delimiter1) From cte2 t Where Substring(@String,t.N,DataLength(@Delimiter1)) = @Delimiter1),
cte4(N,L) As (Select S.N,IsNull(NullIf(CharIndex(@Delimiter1,@String,s.N),0)-S.N,8000) From cte3 S)
Select RetSeq = Row_Number() over (Order By N)
,RetPos = N
,RetVal = left(RetVal,charindex(@Delimiter2,RetVal)-1)
From (
Select *,RetVal = Substring(@String, N, L)
From cte4
) A
Where charindex(@Delimiter2,RetVal)>1
)
/*
Max Length of String 1MM characters
Declare @String varchar(max) = 'Dear [[FirstName]] [[LastName]], ...'
Select * From [dbo].[udf-Str-Extract] (@String,'[[',']]')
*/
如果您可以为此使用SQL Server 2016,则有一个内置的string_split
函数可以完成此工作
SELECT *
FROM YourTable
OUTER APPLY (SELECT SUBSTRING(value, 2, 8000) value
FROM string_split(QuestionTags, '>')
WHERE value <> '') OA
看起来像您正在使用SE数据的Stack Exchange Data Explorer中的演示。
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