初学者使用的Python：掷骰子

Question

我已经从该页面输入了PythonForBeginners的代码，但是如果执行它，它将永远持续下去，并且不会问我是否要再次掷骰子。 我错过了什么？ 应该行吗？

import random
min = 1
max = 6

roll_again = "yes"

while roll_again == "yes" or roll_again == "y":
    print "Rolling the dices..."
    print "The values are...."
    print random.randint(min, max)
    print random.randint(min, max)

    roll_again = raw_input("Roll the dices again?")

Answer 1

做到这一点的一种方法是使用这样的类。

import random
class RollTheDice(object):

    def __init__(self):
        self.min = 1
        self.max = 6
        super(RollTheDice, self).__init__()

    def ask_something(self):
        while True:
            userInput = str(raw_input("Roll Again? Yes or No" + "\n"))
            if (userInput == "Yes" or userInput == 'Y'):
                self.rollDice()
            else:
                print("You didn't type 'Yes' or 'Y' no roll for you. Bye....")
                exit()

    def rollDice(self):
        print "Rolling the dices..."
        print "The values are...."
        print random.randint(self.min, self.max)
        print random.randint(self.min, self.max)

RollTheDiceObject = RollTheDice()
RollTheDiceObject.ask_something()

如果用户没有使用更多代码键入“是”或“ Y”，则我退出程序，您可以使其更智能。

关于while循环的一些信息-https: //www.tutorialspoint.com/python/python_while_loop.htm

Answer 2

我刚和初学者一样在研究相同的问题。 我对您的初始代码做了一些调整，如下所示，它可以正常工作。

 import random
 min = 1
 min = 6

 roll_again = "yes"

 while roll_again == "yes" or roll_again == "y":
   print "You rolled..."
   print random.randint (1,6)
   roll_again = raw_input("Do you want to roll again?")

以下是一种更有效，更优雅的解决方案：

import random 
repeat = True
while repeat:
  print ("You rolled", random.randint(1,6))
  print ("Do you want to roll again? Y/N")
  repeat = ("y" or "yes") in input().lower()