如果语句未检测到字符串或不采取措施

Question

我想做一个与玩家玩摇滚，剪纸，剪刀的机器人。 但是，每次我尝试运行该脚本并输入Stein （德语为Rock）时，if语句都不会检测到该脚本或不执行任何操作。

到目前为止，这是我的代码：

import random
import time

print("Anfangs Buchstaben immer groß schreiben!")

time.sleep(2)

outcomes2 = ("Stein")

Runde = 0

while True:

 Player = input("Deine Wahl: ")

 for i in range(1):
    outcomes = print(random.choice(outcomes2))

 if outcomes == Player:
    print("draw")
    Runde + 1
    continue

Answer 1

第1期

>>> outcomes2 = ("Stein")
>>> print(random.choice(outcomes2))
n

您正在遍历字符串并随机选择一个字符。

我假设您想要：

>>> outcomes2 = ("Stein", )
>>> print(random.choice(outcomes2))
Stein

现在，通过指定,你会遍历字符串的元组（大小为1的元组）。 除非添加更多字符串，否则最终只会得到“ Stein”

outcomes2 = ("Stein", "Name2", "Name3", ...)

第2期

您想要outcomes = random.choice(outcomes2) 。 不要将值分配给print语句，因为print返回None。

把它放在一起...

outcomes2 = ("Stein", )

Runde = 0
while True:
    Player = input("Deine Wahl: ")
    outcomes = random.choice(outcomes2)

    if outcomes == Player:
       print("draw")
       Runde + 1
       continue

Answer 2

`import time
import random
comp_score=0
play_score=0
outcome=('rock','paper','scissor')

while True:     
    player = raw_input("Enter any?");   
    out=random.choice(outcome) 
    print "COMP->"+out      
    if out==player:     
        print "draw"    
    elif out=="rock"and player=="scissor":      
    comp_score+=1;  
    elif out=="scissor" and player=="rock":     
        play_score+=1;  
    elif out=="rock" and player=="paper":   
        play_score+=1;  
    elif out=='paper' and player=='rock':   
        comp_score+=1;  
    elif out=="scissor" and player=="paper": 
            play_score+=1;  
    elif out=='paper' and player=="scissor":
            comp_score+=1;  
    elif player=="quit":        
    break; 
    print "GAME over"
    print "PLayer score: ",play_score
    print "Comp score ",comp_score`