[英]Passing arguments values to shell script
我正在使用以下脚本从CDN中清除缓存,
#!/bin/bash
## API keys ##
zone_id=""
api_key=""
login_id=""
akamai_crd=""
## URL ##
urls="$1"
[ "$urls" == "" ] && { echo "Usage: $0 url"; exit 1; }
echo "Purging $urls..."
curl -X DELETE "https://api.cloudflare.com/client/v4/zones/${zone_id}/purge_cache" \
-H "X-Auth-Email: ${login_id}" \
-H "X-Auth-Key: ${api_key}" \
-H "Content-Type: application/json" \
--data "{\"files\":[\"${urls}\"]}"
#echo "CF is done now purging from Akamai ..."
echo "..."
curl -v -s https://api.ccu.akamai.com/ccu/v2/queues/default -H "Content-Type:application/json" -d '{"objects":["$urls"]}' -u $akamai_crd
当我将其传递给Akamai时,cloudflare的第一部分工作正常,第二部分工作正常
["$urls"]
我不断收到错误消息,并将url作为参数传递,它返回变量本身($ urls)而不是arg值。
我运行脚本如下:
sh +x script.sh url
有什么建议吗?
首先,我将更改此:
SCRIPTNAME=$(basename "$0")
...
if [ $# != 1 ] then
echo "Usage: $SCRIPTNAME url"
exit
fi
$urls="$1"
更改您的第二个curl命令,如下所示(您需要对引号进行转义):
--data "{\"files\":[\"${urls}\"]}"
避免像这样手动创建JSON; 您不能保证所生成的JSON是否已正确转义。 使用类似jq
的工具。
#!/bin/bash
## API keys ##
zone_id=""
api_key=""
login_id=""
akamai_crd=""
## URL ##
url=${1:?Usage: $0 url}
headers=(
-H "X-Auth-Email: $login_id"
-H "X-Auth-Key: $api_key"
-H "Content-Type: application/json"
)
purge_endpoint="https://api.cloudflare.com/client/v4/zones/${zone_id}/purge_cache"
echo "Purging $url..."
jq -n --arg url "$url" '{files: [$url]}' |
curl -X DELETE "$purge_endpoing" "${headers[@]}" --data @-
#echo "CF is done now purging from Akamai ..."
echo "..."
jq -n --arg url "$url" '{objects: [$url]}' |
curl -v -s -H "Content-Type:application/json" -d @- -u "$akamai_crd"
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