[英]How to generate a custom color scale for plotly heatmap in R
我想获得一个自定义的色阶,看起来像是可绘制的热图( plot_ly(z = data, colors = customcolors, type = "heatmap")
)
palette <- colorRampPalette(c("darkblue", "blue", "lightblue1",
"green","yellow", "red", "darkred"))
plot(rep(1,50),col=palette(50), pch=19, cex=3, xlab = "", ylab ="", axes = F)
而蓝色端代表1,红色端代表10 ^ 6,并且绘制的数据在此间隔上具有变化的值。
您用于生成调色板的代码可以正常工作。 您只需要提供与heatmap
匹配的数据即可。 以下代码提供了这一点:
library(RColorBrewer)
library(plotly)
# your palette definition
palette <- colorRampPalette(c("darkblue", "blue", "lightblue1",
"green","yellow", "red", "darkred"))
set.seed(9876) # for reproducibility
## a complete random set
hmdata <- matrix(data = sample(x = 1:10^6, size = 100*100), nrow = 100, ncol = 100)
plot_ly(z = hmdata, colors = palette(50), type = "heatmap")
这给出了以下热图:
## a random set that has been sorted
hmdata_s <- matrix(data = sort(sample(x = 1:10^6, size = 100*100)), nrow = 100, ncol = 100)
plot_ly(z = hmdata_s, colors = palette(50), type = "heatmap")
请让我知道这是否是您想要的。
您可以设置自定义规模plot_ly
与zauto
, zmax
和zmin
。 以下2段代码和图表将说明这一点:
比例尺设置为1到100,数据的变化类似:
hmdata_s3 <- matrix(data = sort(sample(x = 1:100, size = 100*100, replace = TRUE)), nrow = 100, ncol = 100)
plot_ly(z = hmdata_s3, colors = palette(50), type = "heatmap", zauto = FALSE, zmin = 1, zmax = 100)
小数位设置为1到100,数据仅在50到100之间变化
hmdata_s4 <- matrix(data = sort(sample(x = 50:100, size = 100*100, replace = TRUE)), nrow = 100, ncol = 100)
plot_ly(z = hmdata_s4, colors = palette(50), type = "heatmap", zauto = FALSE, zmin = 1, zmax = 100)
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