Python-格式化二进制分类器的CSV数据

Question

我有一些csv数据，格式如下：

headers = [artist_list, song_list, lyrics_track, lyrics_artist, lyrics]`, 

和这个片段：

with open('lyrics.tsv', "rU") as f:
    reader = csv.reader(f, delimiter="\t")
    for i, line in enumerate(reader):
        print 'line[{}] = {}'.format(i, line)

印刷品：

(...)

line[808] = ['Pearl Jam', 'Wishlist', 'Wishlist', 'Pearl Jam', "I wish I was a neutron bomb\nfor once I could go off\nI wish I was a sacrifice\nbut somehow still lived on\nI wish I was a sentimental\nornament you hung on\nthe Christmas tree, I wish I was\nthe star that went on top\nI wish I was the evidence\nI wish I was the grounds\nfor fifty million hands upraised and opened toward the sky\nI wish I was a sailor with\nsomeone who waited for me\nI wish I was as fortunate\nas fortunate as me\nI wish I was a messenger\nand all the news was good\nI wish I was the full moon shining\noff a Camaro's hood\nI wish I was an alien\nat home behind the sun\nI wish I was the souvenir\nyou kept your house key on\nI wish I was the pedal break\nthat you depended on\nI wish I was the verb to trust\nand never let you down\nI wish I was a radio song\nthe one that you turned up\nI wish ..."]

现在我想使用数据进行分类，仅保留所有行的lyrics ，并为二进制值添加一列（始终相同，为0 ），因此数据被转换为：

 lyrics                                                   type

 (...)                                                   (...)

 I wish I was a neutron bomb\nfor once I could go off..    0

我该如何从上面的代码开始呢？

Answer 1

我认为类似这样的方法可能会起作用（假设您的数据位于名为lyrics_df的数据帧中）：

lyrics_df['type']=0