繁体   English   中英

Scala具有名称(标签)的随机森林特征重要性提取

[英]Scala Random forest feature importance extraction with names (labels)

有什么方法可以从模型中提取特征重要性并附加featureCols名称,以便于分析?

我有类似的东西:

val featureCols = Array("a","b","c".......... like 67 more)

val assembler = new VectorAssembler().setInputCols(featureCols).setOutputCol("features")
val df2 = assembler.transform(modeling_db)
val labelIndexer = new StringIndexer().setInputCol("def").setOutputCol("label")
val df3 = labelIndexer.fit(df2).transform(df2)
val splitSeed = 5043
val Array(trainingData, testDataCE) = df3.randomSplit(Array(0.7, 0.3), splitSeed)
val classifier = new RandomForestClassifier().setImpurity("gini").setMaxDepth(19).setNumTrees(57).setFeatureSubsetStrategy("auto").setSeed(5043)
val model = classifier.fit(trainingData)

之后,我们尝试通过以下方式提取重要性:

model.featureImportances

答案确实很难分析:

res14: org.apache.spark.mllib.linalg.Vector = (71,[0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,20,23,25,27,33,34,35,38,39,41,42,45,47,48,49,50,51,52,53,54,55,56,57,58,60,61,62,63,64,65,66,67,68,69,70],[0.22362951804309808,0.1830148359365108,0.10246542303449771,0.1699399958851977,0.06486419413350401,0.05187244974385025,0.02627047699833213,0.014498050071723645,0.026182513062665076,0.007126662761055224,0.012375060477018274,0.004354513006816487,0.004361008357237427,0.008435852744278544,0.003195472326415685,0.0023071401643885753,0.004602370417578224,0.0030394399903992345,6.92408316823549E-4,0.011207695216651398,7.609910745572573E-4,8.316382113306638E-4,0.0021506289318167916,0.0013468620354363688,0.006968754359778437,0.018796331618729723,0.0024516591941419444,0.005980997035580654,0.0027983...

有没有办法“答应”这个答案并将其附加到原始标签名称上?

您在featureCols具有原始列名,并且似乎没有涉及任何向量,因此您只需将两个数组zip在一起即可。 对于这样的输入数据:

val featureCols = Array("a", "b", "c", "d", "e")
val featureImportance = Vectors.dense(Array(0.15, 0.25, 0.1, 0.35, 0.15)).toSparse

简单地做

val res = featureCols.zip(featureImportance.toArray).sortBy(-_._2)

通过打印将导致

(d,0.35)
(b,0.25)
(a,0.15)
(e,0.15)
(c,0.1)

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM